Android 将复杂对象传递给web服务
我正在尝试从我的应用程序调用web服务。如果我调用接受字符串或原语作为输入的web服务方法,那么它可以正常工作,但是当调用接受复杂对象(在我的例子中是样本类)的web服务方法时,我会得到以下错误Android 将复杂对象传递给web服务,android,web-services,ksoap2,Android,Web Services,Ksoap2,我正在尝试从我的应用程序调用web服务。如果我调用接受字符串或原语作为输入的web服务方法,那么它可以正常工作,但是当调用接受复杂对象(在我的例子中是样本类)的web服务方法时,我会得到以下错误 org.apache.axis2.AxisFault: Unknow type {http://spec.com}specimen at org.apache.axis2.databinding.utils.BeanUtil.deserialize(BeanUtil.java:349)
org.apache.axis2.AxisFault: Unknow type {http://spec.com}specimen
at org.apache.axis2.databinding.utils.BeanUtil.deserialize(BeanUtil.java:349)
at org.apache.axis2.databinding.utils.BeanUtil.processObject(BeanUtil.java:827)
at org.apache.axis2.databinding.utils.BeanUtil.ProcessElement(BeanUtil.java:746)
我的发言如下:
我已经在web服务浏览器中测试了我的web服务,它运行良好
package com.spec;
public class Spec {
public String sayHello(String name) // I can successfully invoke this
{
return "Have a great day " + name;
}
public String saveSpecimen(Specimen specimen) // Getting error for this
{
System.out.println("id: " + specimen.getId());
System.out.println("name: " + specimen.getName());
return "Specimend with id " + specimen.getId() + " is successfully saved";
}
}
这是我的样本课
package com.ws;
import java.util.Hashtable;
import org.ksoap2.serialization.KvmSerializable;
import org.ksoap2.serialization.PropertyInfo;
public class Specimen implements KvmSerializable {
int id;
String name;
public Specimen() {
}
public Specimen(int idValue, String nameValue) {
id = idValue;
name = nameValue;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Object getProperty(int arg0) {
if (arg0 == 0)
return id;
else
return name;
}
public int getPropertyCount() {
// TODO Auto-generated method stub
return 2;
}
public void getPropertyInfo(int arg0, Hashtable arg1, PropertyInfo info) {
switch (arg0) {
case 0:
info.type = PropertyInfo.INTEGER_CLASS;
info.name = "id";
break;
case 1:
info.type = PropertyInfo.STRING_CLASS;
info.name = "name";
break;
default:
break;
}
}
public void setProperty(int arg0, Object value) {
switch (arg0) {
case 0:
id = Integer.parseInt(value.toString());
break;
case 1:
name = value.toString();
break;
}
}
}
活动的片段
SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,
OPERATION_NAME);
Specimen specimen = new Specimen();
specimen.setId(1);
specimen.setName("Test_Specimen");
PropertyInfo info = new PropertyInfo();
info.setName("specimen");
info.setValue(specimen);
info.setType(specimen.getClass());
request.addProperty(info);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);
envelope.addMapping(WSDL_TARGET_NAMESPACE, "specimen",new Specimen().getClass());
HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS);
httpTransport.call(SOAP_ACTION, envelope);
SoapObject response = (SoapObject)envelope.getResponse();
Toast.makeText(getApplicationContext(),"Msg from web servce " + response.toString(),Toast.LENGTH_LONG).show();
我想问题出在你身上
envelope.addMapping(WSDL_TARGET_NAMESPACE, "specimen",new Specimen().getClass());
下面是我在wsdl文件中的复杂类型声明示例
<xs:schema attributeFormDefault="qualified" elementFormDefault="qualified" argetNamespace="http://spec.com/xsd">
<xs:complexType name="Specimen">
<xs:sequence>
<xs:element minOccurs="0" name="id" type="xs:int"/>
<xs:element minOccurs="0" name="name" nillable="true" type="xs:string"/></xs:sequence></xs:complexType>
</xs:schema>
如果我犯了什么错误,请告诉我
谢谢 试试这个:
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("Specimen", specimen);
SoapSerializationEnvelope envelope =
new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
envelope.addMapping("http://spec.com/xsd", "Specimen", new Specimen().getClass());
try {
HttpTransportSE transport = new HttpTransportSE(SOAP_ADDRESS);
transport.call(NAMESPACE + METHOD_NAME, envelope);
Object response = envelope.getResponse();
String result = response.toString();
/* make a toast ... */
} catch (Exception e) {
e.printStackTrace();
}
如果不起作用,请发布您的WSDL\u目标\u命名空间、操作\u名称和地址字符串。尝试以下操作:
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("Specimen", specimen);
SoapSerializationEnvelope envelope =
new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
envelope.addMapping("http://spec.com/xsd", "Specimen", new Specimen().getClass());
try {
HttpTransportSE transport = new HttpTransportSE(SOAP_ADDRESS);
transport.call(NAMESPACE + METHOD_NAME, envelope);
Object response = envelope.getResponse();
String result = response.toString();
/* make a toast ... */
} catch (Exception e) {
e.printStackTrace();
}
如果它不起作用,请发布您的WSDL\u目标\u名称空间、操作\u名称和地址字符串。尝试了很多,但都没有成功。所以,将web服务更新为简单的参数,并传递对象中存在的所有属性。尝试了很多,但无法使其工作。因此,将web服务更新为简单参数并传递对象中存在的所有属性。尝试使其成为大写信封。addMapping(WSDL_TARGET_名称空间,“sample”,new sample().getClass());看看它是否有效?我不确定。@hrishikeshp19:运气不佳..您访问过这里吗->?尝试制作大写信封.addMapping(WSDL_TARGET_名称空间,“sample”,new sample().getClass());看看它是否有效?我不确定。@hrishikeshp19:没有运气。.你访问过这里吗->?尝试过你的建议,但没有运气得到
ArrayIndexOutofBoundExeption
。可能是错误妨碍了我得到响应,请尝试更改该行。我想其余的都没问题。@enmarc:我不认为Envelope.getResponse
会导致arrayIndexOutofBoundException
尝试了你的建议,但没有成功获得arrayIndexOutofBoundException
。可能是错误妨碍了我获得响应,尝试更改那一行。我认为其余的都可以。@enmarc:我不认为Envelope.getResponse
会导致arrayIndexOutofBoundException