android选项卡项onClick不';行不通
我有功能cityClick, 如果我从textView调用此函数,它工作正常,但如果我从TabItem调用cityClick,它不工作,发生了什么 爪哇 布局android选项卡项onClick不';行不通,android,onclick,tabitem,Android,Onclick,Tabitem,我有功能cityClick, 如果我从textView调用此函数,它工作正常,但如果我从TabItem调用cityClick,它不工作,发生了什么 爪哇 布局 <android.support.design.widget.TabLayout android:id="@+id/tabs" android:layout_width="match_parent" android:layout_height="wrap_content"
<android.support.design.widget.TabLayout
android:id="@+id/tabs"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:gravity="center"
android:clickable="true"
android:onClick="cityClick"
app:tabMode="fixed">
<android.support.design.widget.TabItem
android:layout_height="wrap_content"
android:layout_width="match_parent"
android:textAlignment="center"
android:textSize="18sp"
android:onClick="cityClick"
android:clickable="true"
android:text="GDAŃSK" />
<android.support.design.widget.TabItem
android:layout_height="wrap_content"
android:layout_width="match_parent"
android:textAlignment="center"
android:textSize="18sp"
android:onClick="cityClick"
android:clickable="true"
android:text="SOPOT" />
<android.support.design.widget.TabItem
android:layout_height="wrap_content"
android:layout_width="match_parent"
android:textAlignment="center"
android:textSize="18sp"
android:onClick="cityClick"
android:clickable="true"
android:text="GDYNIA" />
</android.support.design.widget.TabLayout>
我在这个论坛上搜索,但没有找到任何帮助。试试这个
tabs.addOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
Toast.makeText(mActivity, "hai", Toast.LENGTH_SHORT).show();
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
在科特林
tabs.addOnTabSelectedListener(object:TabLayout.OnTabSelectedListener {
override fun onTabSelected(tab : TabLayout.Tab) {
Toast.makeText(mActivity, tab.text, Toast.LENGTH_SHORT).show()
}
override fun onTabUnselected(p0: TabLayout.Tab?) {
}
override fun onTabReselected(p0: TabLayout.Tab?) {
}
})
由于可能存在多个选项卡,这将更加完整:
TabLayout.addOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
switch (tab.getPosition()) {
case 0:
// codes related to the first tab
break;
case 1:
// codes related to the second tab
break;
case 2:
// codes related to the third tab
break;
case 3:
// codes related to the fourth tab
break;
.
.
.
}
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
检查这是否有效。这里的解决方案从少到复杂,有没有一种简单的方法来调用一个小函数,而不需要几十行额外的代码?我想选民们应该给出一个解决方案……对我来说,这是一个符合SO准则的有效问题……没有理由否决投票。@slawek:您是否在textView中使用了完全相同的
cityClick
?是的,这与textView的功能和工作原理相同
TabLayout.addOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
switch (tab.getPosition()) {
case 0:
// codes related to the first tab
break;
case 1:
// codes related to the second tab
break;
case 2:
// codes related to the third tab
break;
case 3:
// codes related to the fourth tab
break;
.
.
.
}
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});