Android 可访问性服务

我创建了以下代码： （AccActivity.java）

And（Access.java）-扩展AccessibilityService

import android.accessibilityservice.AccessibilityService;
import android.accessibilityservice.AccessibilityServiceInfo;
import android.content.Context;
import android.util.Log;
import android.view.accessibility.AccessibilityEvent;

public class Access extends AccessibilityService{

private static final long EVENT_NOTIFICATION_TIMEOUT_MILLIS = 50;


@Override
public void onAccessibilityEvent(AccessibilityEvent arg0) {
    // TODO Auto-generated method stub
    Log.d("TAS", "onAccessibilityEvent");

}

@Override
public void onInterrupt() {
    // TODO Auto-generated method stub
    Log.d("TAS", "onInterrupt");
}

@Override
protected void onServiceConnected (){
    // TODO Auto-generated method stub
    Log.d("TAS", "onServiceConnected");
    setServiceInfo();
}

 private void setServiceInfo() {
        AccessibilityServiceInfo info = new AccessibilityServiceInfo();
        // We are interested in all types of accessibility events.
        info.eventTypes = AccessibilityEvent.TYPES_ALL_MASK;
        // We want to provide specific type of feedback.
        info.feedbackType = AccessibilityServiceInfo.FEEDBACK_GENERIC;
        // We want to receive events in a certain interval.
        info.notificationTimeout = EVENT_NOTIFICATION_TIMEOUT_MILLIS;
        // We want to receive accessibility events only from certain packages.
        info.packageNames = new String[1];
        // only handle this package
        info.packageNames[0] = getPackageName();  
        setServiceInfo(info);

  }
}

并表明：

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="bad.android.acc"
android:versionCode="1"
android:versionName="1.0" >

<uses-sdk android:minSdkVersion="10" />

<application
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name" >
    <activity
        android:label="@string/app_name"
        android:name=".AccActivity" >
        <intent-filter >
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

 <service android:name=".Access">
<intent-filter>
    <action android:name="android.accessibilityservice.AccessibilityService" />
</intent-filter>
</service>

</application>
</manifest>

现在，如何启动服务可访问性“Access.java”？作为正常服务？我对这项服务有点困惑。。 谢谢

这可以帮助您：

---

MIUI上隐藏了“可访问性”，您应该按“搜索”按钮并输入“可访问性”（可能是中文）辅助功能" ), 然后你可以打开它。

我理解了你的问题，你似乎想打开辅助功能设置

如果是，以下代码将启动辅助功能设置：

Intent intent = new Intent(android.provider.Settings.ACTION_ACCESSIBILITY_SETTINGS);
startActivityForResult(intent, 0);

---

谢谢，我明白了，我已经解决了。我不知道如何将服务打开为MIUI，因为菜单“可访问性”已被隐藏。

Intent intent = new Intent(android.provider.Settings.ACTION_ACCESSIBILITY_SETTINGS);
startActivityForResult(intent, 0);