Android 错误:类型不匹配:无法从void转换为java.lang.String
我不断地发现这个错误: 类型不匹配:无法从void转换为my的java.lang.String 对话框 我试图让名称与计算一起显示在对话框中,但我得到了上面的错误Android 错误:类型不匹配:无法从void转换为java.lang.String,android,Android,我不断地发现这个错误: 类型不匹配:无法从void转换为my的java.lang.String 对话框 我试图让名称与计算一起显示在对话框中,但我得到了上面的错误 public static void main(String[] args) { final double tax_Rate = .08; final double bonus_Pay_Rate = .1; String name = JOptionPane.showInputDialog("Please en
public static void main(String[] args)
{
final double tax_Rate = .08;
final double bonus_Pay_Rate = .1;
String name = JOptionPane.showInputDialog("Please enter your name");
String hr = JOptionPane.showInputDialog("Please enter your hourly rate");
double hourlyRate = Double.parseDouble(hr);
String hw = JOptionPane.showInputDialog("Please enter your hours worked");
double hoursWorked = Double.parseDouble(hw);
double tax = (hoursWorked * hourlyRate) * tax_Rate;
double pay = hoursWorked * hourlyRate - tax;
double weeksPay = (pay * bonus_Pay_Rate) + pay;
String aswner = JOptionPane.showMessageDialog(null, (name) + "'s" + "pay this week is: $" + (weeksPay));
您正在尝试将void指定给字符串
String aswner = JOptionPane.showMessageDialog(null,... );
showMessageDialog
返回一个void
,而不是字符串
请让您的代码更易于阅读,准确地告诉我们错误发生的位置,并删除所有与问题没有直接关系的代码。但是,我怀疑您的问题是所有看起来像
String name=JOptionPane.showInputDialog(“…”)的行代码>。我打赌showInputDialog
返回void,您正试图将其分配给字符串。