mysql soap调用在android设备上不起作用

mysql soap调用在android设备上不起作用,android,mysql,web-services,android-emulator,ksoap2,Android,Mysql,Web Services,Android Emulator,Ksoap2,我已经在android应用程序中开发了一个登录表单,调用mysql数据库调用soap webservices。它在android emulator上成功运行。但在android real device上没有运行。请说明我能做什么。请说明这里发生了什么 我的android代码是: package com.androidlogin.ws; import java.net.SocketException; import android.util.Log; import org.ksoap2.SoapE

我已经在android应用程序中开发了一个登录表单,调用mysql数据库调用soap webservices。它在android emulator上成功运行。但在android real device上没有运行。请说明我能做什么。请说明这里发生了什么

我的android代码是:

package com.androidlogin.ws;
import java.net.SocketException;
import android.util.Log;
import org.ksoap2.SoapEnvelope;
import org.ksoap2.serialization.PropertyInfo;
import org.ksoap2.serialization.SoapObject;
import org.ksoap2.serialization.SoapPrimitive;
import org.ksoap2.serialization.SoapSerializationEnvelope;
import org.ksoap2.transport.HttpTransportSE;
import android.app.Activity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;

public class AndroidLoginExampleActivity extends Activity {
private final String NAMESPACE = "http://ws.userlogin.com";
private final String URL = "http://111.223.128.10:8085/AndroidLogin/services/Login?wsdl";
private final String SOAP_ACTION = "http://ws.userlogin.com/authentication";
private final String METHOD_NAME = "authentication";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    Button login = (Button) findViewById(R.id.btn_login);
    login.setOnClickListener(new View.OnClickListener() {

 public void onClick(View arg0) {
  loginAction();

  }
  });
  }

    private void loginAction(){
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    EditText userName = (EditText) findViewById(R.id.tf_userName);
    String user_Name = userName.getText().toString();
    EditText userPassword = (EditText) findViewById(R.id.tf_password);
    String user_Password = userPassword.getText().toString();

  //Pass value for userName variable of the web service
    PropertyInfo unameProp =new PropertyInfo();
    unameProp.setName("userName");//Define the variable name in the web service method
    unameProp.setValue(user_Name);//set value for userName variable
    unameProp.setType(String.class);//Define the type of the variable
    request.addProperty(unameProp);//Pass properties to the variable

  //Pass value for Password variable of the web service
    PropertyInfo passwordProp =new PropertyInfo();
    passwordProp.setName("password");
    passwordProp.setValue(user_Password);
    passwordProp.setType(String.class);
    request.addProperty(passwordProp);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.setOutputSoapObject(request);
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
     ServiceConnection connection = getServiceConnection();
        connection.connect();
    try{
      connection.setConnectTimeout(60000);
        androidHttpTransport.call(SOAP_ACTION, envelope);
           SoapPrimitive response = (SoapPrimitive)envelope.getResponse();

           TextView result = (TextView) findViewById(R.id.tv_status);
           result.setText(response.toString());

    }


   catch(SocketException ex)
     {
   Log.e("Error : " , "Error on soapPrimitiveData() " + ex.getMessage());
     ex.printStackTrace();
     }

    }
    protected ServiceConnection getServiceConnection() throws IOException {
     return new AndroidServiceConnection(URL);
      }

      }
在我的注销窗口上显示dis消息: 07-20 04:26:22.728:D/SntpClient(71):请求时间失败:java.net.SocketException:协议不支持地址系列


但是我的ip地址.端口号都是正确的。

请尝试将其添加到您的
AndroidManifest.xml
中:

<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
更新

尝试在清单文件中添加以下权限:

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.WAKE_LOCK"/> 
<uses-permission android:name="android.permission.CHANGE_WIFI_STATE" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
在try块中,写入以下内容:

     connection.setConnectTimeout(60000); //put a large value for timeout
创建以下方法:

     protected ServiceConnection getServiceConnection() throws IOException {
        return new AndroidServiceConnection(url);
    }

请重新运行代码,然后立即重试。

发布您的代码,您遇到了什么异常我已经添加了您的代码..请立即查看我的代码部分。在dis行中有错误:catch(SocketException ex)。错误是:此行有多个标记-SocketException无法访问catch块。它已经由catch块处理,用于异常行断点:AndroidWSDLFrontEnd[Line:41]-onCreate(Bundle)…请如何清除dis error删除第一个catch块并重试。请确保大括号已正确关闭它正在影响我的try块…请再次查看我的更新代码。因为我缺少第一个catch块代码。现在已插入。在此处进行更改:catch(异常e){e.printStackTrace();((TextView)findViewById(R.id.txtAddition)).setText(“错误:+e.getClass().getName()+”:“+e.getMessage())}我已更改了代码。但这影响了我的try块。调用(SOAP_操作,信封);SoapPrimitive响应=(SoapPrimitive)信封.getResponse();上述行必须显示以下错误:此行有多个标记-未处理的异常类型IOException-未处理的异常类型XmlPullParseRexException
     connection.setConnectTimeout(60000); //put a large value for timeout
     protected ServiceConnection getServiceConnection() throws IOException {
        return new AndroidServiceConnection(url);
    }