删除请求参数URL截取android

我有一个API，带有如下的删除函数：

String baseUrl ="http://localhost/v1/deletePost/";
String url = baseUrl + "3" //Here you change the ID, can put as variable

// Request a string response from the provided URL.
StringRequest stringRequest = new StringRequest(Request.Method.DELETE, url, 
new Response.Listener<String>() {
    @Override
    public void onResponse(String response) {
        // Display the first 500 characters of the response string.
        mTextView.setText("Response is: "+ response.substring(0,500));
    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError error) {
        mTextView.setText("That didn't work!");
    }
});

当我尝试使用postman时，通过在url:id like../deletePost/37中输入param成功

如何使用Volley库在android中实现/：id请求？

下面是一个关于如何使用Volley库的示例

在发送简单请求的页面上：

final TextView mTextView = (TextView) findViewById(R.id.text);
//...

// Instantiate the RequestQueue.
RequestQueue queue = Volley.newRequestQueue(this);
String url ="http://www.google.com";

// Request a string response from the provided URL.
StringRequest stringRequest = new StringRequest(Request.Method.GET, url, 
new Response.Listener<String>() {
    @Override
    public void onResponse(String response) {
        // Display the first 500 characters of the response string.
        mTextView.setText("Response is: "+ response.substring(0,500));
    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError error) {
        mTextView.setText("That didn't work!");
    }
});
// Add the request to the RequestQueue.queue.add(stringRequest);

---

您只需使用URL字符串URL=http://localhost/v1/deletePost; 字符串id=/+3字符串finalUrl=url+id；你有任何示例代码吗？在我尝试之后，他的回答发出了400错误：02-10 11:16:12.877 25325-25368/？E/Volley:[4113]BasicNetwork.performRequest:@UpendraShahString DELETEADD=String id=/+id_post的意外响应代码400；字符串finalUrl=DELETEADD+id；请检查我的更新问题，我添加了照片@UpendraShahI在文档中没有找到它。好的，我会试试@Canato