Angular 7 routes concat导致编译错误

首先-仅供参考，路由模块设置为：

@NgModule({
  imports: [RouterModule.forRoot(ALL_ROUTES)],
  exports: [RouterModule],
  providers: []
})
export class AppRoutingModule {}

将所有路由放置在名为“all_routes”的1个数组中，并将该数组传递给AppRoutingModule-imports:[RouterModule.forRoot（all_routes）]，效果良好：

export const ALL_ROUTES: Routes = [
  {path: 'route1', component: FirstComponent},
  {path: 'route2', component: SecondComponent},
  {path: 'route3', component: ThirdComponent},
  {path: 'route4', component: FourthComponent}
];

因此，上面的代码运行良好。 但是，如果我们有2个数组，并按如下方式对它们进行处理：

export const ROUTES1: Routes = [
  {path: 'route1', component: FirstComponent},
  {path: 'route2', component: SecondComponent}
];

export const ROUTES2: Routes = [
  {path: 'route3', component: ThirdComponent},
  {path: 'route4', component: FourthComponent}
];

export const ALL_ROUTES: Routes = ROUTES1.concat(ROUTES2);

我们得到一个编译错误：

ERROR in Cannot read property 'loadChildren' of undefined

---

这里已经提出了两个类似的问题，但没有解决这个问题。有可能的解决办法吗？可能是对正在发生的事情的一种解释？

对于那些正在搜索带有答案的帖子的人来说——正如上面Danil所建议的，这是可行的。如果有任何潜在问题，请发表评论

export const ALL_ROUTES: Routes =
    [
      ...ROUTES1,
      ...ROUTES2
    ];

你也可以试试

const supportedGames: Route[] = [
    {
        path: "pubg",
        component: LoginComponent
    }
];

const routes: Routes = [
    {
        path: "",
        component: LoginComponent,
    },
    {
        path: "login",
        component: LoginComponent,
    },
    {
        path: "main",
        component: MainViewComponent,
        children: ([
            {
                path: "game-list",
                component: GameListComponent,
            }
        ] as Route[]).concat(supportedGames)
    },
    {
        path: "**",
        redirectTo: ""
    }
];

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尝试类似于导出const ALL_ROUTES:ROUTES=[…ROUTES 1，…ROUTES 2]似乎正在工作。非常感谢。