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Angularjs 通过包含多个嵌套项的json文件进行解析_Angularjs_Json - Fatal编程技术网

Angularjs 通过包含多个嵌套项的json文件进行解析

Angularjs 通过包含多个嵌套项的json文件进行解析,angularjs,json,Angularjs,Json,AIOI在下面有这个JSON文件,由jsonlint.com整理。我有一个问题,确定正确的角度点向下的方法,以获得第一个名字 {{complaints.FileNum}} 将提交:案例1 {{complaints.AIO[0].AIO_ID}} 将呈现:3 {{complaints.AIO.CRINVOLVED[0].Firstname}} OR {{complaints.AIO.CRINVOLVED[0].Firstname}} 不会有任何结果。请说明我做错了什么 { "AIO

AIOI在下面有这个JSON文件,由jsonlint.com整理。我有一个问题,确定正确的角度点向下的方法,以获得第一个名字

{{complaints.FileNum}}
将提交:案例1

{{complaints.AIO[0].AIO_ID}} 
将呈现:3

{{complaints.AIO.CRINVOLVED[0].Firstname}} OR     {{complaints.AIO.CRINVOLVED[0].Firstname}}
不会有任何结果。请说明我做错了什么

{
"AIO": [{
    "ALLEGATIONS": [],
    "CRINVOLVED": {
        "ASSOC_INC_OFF": [],
        "FirstName": "Joe",
        "MiddleName": null,
        "LastName": "Do",
        "DateOfBirth": null,
        "Hired_DT": null,
        "Race": null,
        "Rank": null,
        "District": null,
        "OffDuty": null,
        "Sex": null,
        "Ethnicity": null,
        "OfficerType": null,
        "OIMOnly": null,
        "CompID": null,
        "OFCNUM": 2,
        "AIO_ID": null,
        "BadgeNo": "P12345",
        "Department": null
    },
    "AIO_ID": 3,
    "COMP_ID": 1,
    "OFCNUM": 2,
    "LINK_TYPE": null
}],
"COMP_ID": 1,
"FileNum": "case1",
"Received_DT": "2016-01-21T00:00:00",
"CRORoute_DT": "2015-10-07T00:00:00"
}

我想你想要这个:
complaints.AIO[0].CRINVOLVED.FirstName
Object.Array[index].Object.field

complaints.AIO[0].CRINVOLVED.FirstName
拉小提琴:

这应该做到:

 {{foo.ASSOC_INC_OFF[0].CRINVOLVED["FirstName"]}}

虽然这个代码块可能会回答这个问题,但如果您能提供一些解释来解释为什么它会这样做,那将是最好的。