Angularjs 向UI路由器路由添加查询字符串
我有一个ui路由器路由,定义如下Angularjs 向UI路由器路由添加查询字符串,angularjs,angular-ui-router,Angularjs,Angular Ui Router,我有一个ui路由器路由,定义如下 $stateProvider .state('search', { url: '/search', abstract: true, parent: 'loggedIn', views: { wrapper: { controller: 'MyCtrl',
$stateProvider
.state('search', {
url: '/search',
abstract: true,
parent: 'loggedIn',
views: {
wrapper: {
controller: 'MyCtrl',
controllerAs: 'myCtrl',
templateUrl: '/scripts/views/search/views/search.wrapper.html'
}
}
})
.state('search.subs', {
url: '',
resolve: {
isLoggedIn: isLoggedIn
},
views: {
body: {
controller: 'SearchBodyCtrl',
controllerAs: 'searchBodyCtrl',
templateUrl: '/scripts/views/search/views/search.body.html'
}
}
});
无论如何,问题是我无法生成一个查询参数,使url看起来像
/search?hello=world
我尝试使用$state.transition('search.subs',{hello:'world})
,但这不起作用。我认为我传递的任何不匹配的参数都会被放入查询字符串中,但事实并非如此 这应该是您想要做的:
.state('search.subs', {
url: '?hello', // This appends to the parent url
....
之后,您可以使用$state.go('search.subs',{hello:'world'})
转换到search.subs状态
是的,我真的希望有一个动态API,但事实证明没有(