Ansible-如果不存在，则插入行，并且不'；如果存在以空格分隔的行，则不插入

我使用lineinfle模块插入一条不存在的线，但当它存在多个空格时，它仍然插入一条线

输入：

one two three

(not exists)     < Insert
one two three    < Don't insert (it's correct)
one  two  three  < Don't insert (having same words but multiple spaces)

- lineinfile: 
    path: /somefile
    line: 'one two three'

Before : one  two  three
After  : one  two  three
         one two three

期望：

one two three

(not exists)     < Insert
one two three    < Don't insert (it's correct)
one  two  three  < Don't insert (having same words but multiple spaces)

- lineinfile: 
    path: /somefile
    line: 'one two three'

Before : one  two  three
After  : one  two  three
         one two three

我的输出：

one two three

(not exists)     < Insert
one two three    < Don't insert (it's correct)
one  two  three  < Don't insert (having same words but multiple spaces)

- lineinfile: 
    path: /somefile
    line: 'one two three'

Before : one  two  three
After  : one  two  three
         one two three

问：“期待”

给定test.txt文件

shell>cat test.txt
123

此任务的剧本给出了

shell>ansible剧本pb.yml
shell>cat test.txt
123
456

作为下一个示例，下面的

regexp

给出了相同的结果，并将序列限制为仅空白。单词之间必须至少有一个空格

-lineinfle:
路径：test.txt
regexp:“^（\s*）{{item.0}（\s+{{item.1}}（\s+{{item.2}}（\s*）$”
行：“{item.0}}{{item.1}{{{item.2}”
循环：
-一、二、三
-四、五、六

---

背景参考

可以保留现有线条的间距。看见但是，不存在的行将不会被添加

-lineinfle:
背景：是的
路径：test.txt
regexp:“^（.*）{{item.0}}（.*）{{item.1}（.*）{{item.2}}（.*）”
行：“{item.0}}\2{{item.1}}\3{{item.2}”
循环：
-一、二、三
-四、五、六

例如，给定相同的文件

shell>cat test.txt
123

具有此任务的剧本跳过迭代，并且不做任何更改

shell>ansible剧本pb.yml
shell>cat test.txt
123