Arrays 希望创建一个4x10表，使用foreach循环以速度列出我的数组

我想循环遍历第一行中的数组清单[1-4]，第二行中的数组清单[5-8]，然后继续循环，直到输出整个数组

#set ($cats = [
  "Accounting", "Admin & Clerical", "Automotive", "Banking", 
  "Broadcast - Journalism", "Business Development", "Construction", "Customer Service",
  "Design", "Distribution - Shipping", "Education - Teaching", "Facilities",
  "Finance", "General Business", "General Labor", "Government", 
  "Grocery", "Health Care", "Hotel - Hospitality", "Human Resources", 
  "Installation - Maint - Repair", "Inventory", "Legal Admin", "Management",
  "Manufacturing", "Marketing", "Nurse", "Pharmaceutical",
  "Purchasing - Procurement", "QA - Quality Control", "Real Estate", "Research",
  "Restaurant - Food Service", "Retail", "Sales", "Skilled Labor - Trades",
  "Strategy - Planning", "Supply Chain", "Transportation", "Warehouse"
] )

如何获取数组中的前4项，将它们放在一行中，然后移动到下4项

<table cellpadding="5px" cellspacing="0" width="100%" style="width:100%!important;font-size:9px;font-family: Arial, 'Helvetica Neue', Helvetica, sans-serif;font-weight:normal;text-align:center;background:;color:black">
  #set ($counter = 0)
  #set ($j = )
  #foreach ($i in $cats)
    #if ( $counter % 2 == 0)
    <tr>
      <td>$i</td>
      <td></td>
      <td></td>
      <td></td>
    </tr>
    #else
    <tr>
      <td></td>
      <td></td>
      <td></td>
      <td></td>
    </tr>
    #end
  #end

</table>

#设置（$counter=0）
#集合（$j=）
#foreach（$猫中的i）
#如果（$counter%2==0）
$i
#否则
#结束
#结束

我一点也不知道速度，但根据我对其他编码语言的了解，试试这样的方法，让我知道它是如何运行的

<table cellpadding="5px" cellspacing="0" width="100%" style="width:100%!important;font-size:9px;font-family: Arial, 'Helvetica Neue', Helvetica, sans-serif;font-weight:normal;text-align:center;color:black">
  <!-- The two sets in your code here looked superfluous --!>
  #foreach ($i in $cats)
    #if ( ( $foreach.index - 1 ) % 4 == 0)
      <tr>
    #end
    <td>$i</td>
    #if ( ( $foreach.index - 1 ) % 4 == 3 || $foreach.last)
      </tr>
    #end
  #end

</table>

那很好。祝你好运。你有问题吗？我的问题是如何抓住数组的前4个并将它们放在一行中，然后移动到下4个