Arrays Ruby:根据条件迭代和嵌套哈希
我有两个哈希数组,如下所示:Arrays Ruby:根据条件迭代和嵌套哈希,arrays,ruby,hash,Arrays,Ruby,Hash,我有两个哈希数组,如下所示: h1=[{id:1, item:1, from: DateTime.new(2017,9,4,6,0,0,'+0300'), to: DateTime.new(2017,9,4,17,59,59,'+0300'), value:10}, {id:1, item:2, from: DateTime.new(2017,9,4,18,0,0,'+0300'), to: DateTime.new(2017,9,4,23,59,59,'+0300'), value:1
h1=[{id:1, item:1, from: DateTime.new(2017,9,4,6,0,0,'+0300'), to: DateTime.new(2017,9,4,17,59,59,'+0300'), value:10},
{id:1, item:2, from: DateTime.new(2017,9,4,18,0,0,'+0300'), to: DateTime.new(2017,9,4,23,59,59,'+0300'), value:10}]
h2=[{id:1, item:1, date: DateTime.new(2017,9,4,6,10,0,'+0300'), value:5},
{id:2, item:1, date: DateTime.new(2017,9,4,7,20,0,'+0300'), value:7},
{id:3, item:1, date: DateTime.new(2017,9,4,8,05,0,'+0300'), value:10},
{id:4, item:1, date: DateTime.new(2017,9,4,18,19,10,'+0300'), value:1},
{id:5, item:2, date: DateTime.new(2017,9,4,19,20,0,'+0300'), value:2},
{id:6, item:2, date: DateTime.new(2017,9,4,22,22,0,'+0300'), value:5},
{id:7, item:2, date: DateTime.new(2017,9,5,23,0,0,'+0300'), value:1}]
=> [:order=>{:id=>1,
:item=>1,
:from=>Mon, 04 Sep 2017 06:00:00 +0300,
:to=>Mon, 04 Sep 2017 17:59:59 +0300,
:value=>10,
:inventory=>
{:id=>1, :item=>1, :date=>Mon, 04 Sep 2017 06:10:00 +0300, :value=>5},
{:id=>2, :item=>1, :date=>Mon, 04 Sep 2017 07:20:00 +0300, :value=>7},
{:id=>3, :item=>1, :date=>Mon, 04 Sep 2017 08:05:00 +0300, :value=>10}
:order=>{:id=>1,
:item=>2,
:from=>Mon, 04 Sep 2017 18:00:00 +0300,
:to=>Mon, 04 Sep 2017 23:59:59 +0300,
:value=>10,
:inventory=>
{:id=>4, :item=>2, :date=>Mon, 04 Sep 2017 18:19:10 +0300, :value=>1},
{:id=>5, :item=>2, :date=>Mon, 04 Sep 2017 19:20:00 +0300, :value=>2},
{:id=>6, :item=>2, :date=>Mon, 04 Sep 2017 22:22:00 +0300, :value=>5},
{:id=>7, :item=>2, :date=>Mon, 04 Sep 2017 23:00:00 +0300, :value=>1}}]
我需要在每个h1
下嵌套h2
中符合条件的任何哈希:
item
值(例如,两个哈希中的item:1
)date
fromh2
在from
-到范围内h1
h1
下,使用以下内容:
my_hash = h1.each do
|mh| mh[:inventory]=h2
end
my_hash = h1.each do |hsh|
h2.each do |hsh2|
hash=hsh2.find{|h| h[:item] == hsh[:item] && h[:date].between?(hsh[:from],hsh[:to])} if hash
hsh[:inventory] = hash
end
end
我相信可以通过以下方式实现:
h2.find{ |i| i[:item] == h1[:item] && i[:date].between?(h2[:from], h2[:to]) }
请问,我如何将其组合起来才能使其工作?谢谢大家!强>
更新2
我试图为每个h1
匹配的h2
查找与此匹配的哈希:
my_hash = h1.each do
|mh| mh[:inventory]=h2
end
my_hash = h1.each do |hsh|
h2.each do |hsh2|
hash=hsh2.find{|h| h[:item] == hsh[:item] && h[:date].between?(hsh[:from],hsh[:to])} if hash
hsh[:inventory] = hash
end
end
但是,我从(pry):12:的“hash”中得到错误的参数数目(给定1,预期为0)。
请问我做错了什么
更新3
如果可能,理想输出如下:
h1=[{id:1, item:1, from: DateTime.new(2017,9,4,6,0,0,'+0300'), to: DateTime.new(2017,9,4,17,59,59,'+0300'), value:10},
{id:1, item:2, from: DateTime.new(2017,9,4,18,0,0,'+0300'), to: DateTime.new(2017,9,4,23,59,59,'+0300'), value:10}]
h2=[{id:1, item:1, date: DateTime.new(2017,9,4,6,10,0,'+0300'), value:5},
{id:2, item:1, date: DateTime.new(2017,9,4,7,20,0,'+0300'), value:7},
{id:3, item:1, date: DateTime.new(2017,9,4,8,05,0,'+0300'), value:10},
{id:4, item:1, date: DateTime.new(2017,9,4,18,19,10,'+0300'), value:1},
{id:5, item:2, date: DateTime.new(2017,9,4,19,20,0,'+0300'), value:2},
{id:6, item:2, date: DateTime.new(2017,9,4,22,22,0,'+0300'), value:5},
{id:7, item:2, date: DateTime.new(2017,9,5,23,0,0,'+0300'), value:1}]
=> [:order=>{:id=>1,
:item=>1,
:from=>Mon, 04 Sep 2017 06:00:00 +0300,
:to=>Mon, 04 Sep 2017 17:59:59 +0300,
:value=>10,
:inventory=>
{:id=>1, :item=>1, :date=>Mon, 04 Sep 2017 06:10:00 +0300, :value=>5},
{:id=>2, :item=>1, :date=>Mon, 04 Sep 2017 07:20:00 +0300, :value=>7},
{:id=>3, :item=>1, :date=>Mon, 04 Sep 2017 08:05:00 +0300, :value=>10}
:order=>{:id=>1,
:item=>2,
:from=>Mon, 04 Sep 2017 18:00:00 +0300,
:to=>Mon, 04 Sep 2017 23:59:59 +0300,
:value=>10,
:inventory=>
{:id=>4, :item=>2, :date=>Mon, 04 Sep 2017 18:19:10 +0300, :value=>1},
{:id=>5, :item=>2, :date=>Mon, 04 Sep 2017 19:20:00 +0300, :value=>2},
{:id=>6, :item=>2, :date=>Mon, 04 Sep 2017 22:22:00 +0300, :value=>5},
{:id=>7, :item=>2, :date=>Mon, 04 Sep 2017 23:00:00 +0300, :value=>1}}]
对于每个
h1
我想给出新的键顺序
,然后在inventory
键下嵌套适当的h2
散列。这在ruby 2.4.2p198(2017-09-14修订版59899)[x64-mingw32]
h1.each do |hsh1|
hsh1[:inventory] =
h2.find do |hsh2|
hsh2[:item] == hsh1[:item] &&
hsh2[:date].between?(hsh1[:from],hsh1[:to])
end || Hash.new
end
您可以通过用所需的默认值替换
散列来使用默认值hsh1[:inventory]。new
。是否可以添加预期的输出?两个输入散列中都没有键:inventory
。@SebastiánPalma,请参阅上面我的更新3,其中我添加了输出示例+扩展了我关于父项和子项哈希键的问题。@mudasobwa请参阅上面我的更新3,其中我用输出示例清除了我的问题。谢谢,但是它似乎只将h2
中的单个哈希嵌套在h1
下,不可能全部嵌套。请看一下我上面的更新3,我添加了输出示例并澄清了我的问题,好吗?愚蠢的我,我可以用find_all
替换find_all
,然后它将嵌套所有符合我的条件的哈希:)