Arrays Swift如何基于另一个数组筛选数组

我有一个数组

VIPArray

和

AddressArray

，因此我想根据

VIPArray

过滤

AddressArray

。我该怎么做

VIPArray

看起来像这样

let VIPArray = [["name": "John B"], ["name": "Sara K"]]

let AddressArray = [Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
                    Address(name: "Dave H",  imageURL: "daveh", address: "1011 Victoria St.."),
                    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av."),
                    Address(name: "Niles K", imageURL: "nilesk", address: "45 King St."),
                    Address(name: "Ingrid G",  imageURL: "ingridg", address: "33 Union St.")

AddressArray

如下所示

let VIPArray = [["name": "John B"], ["name": "Sara K"]]

let AddressArray = [Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
                    Address(name: "Dave H",  imageURL: "daveh", address: "1011 Victoria St.."),
                    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av."),
                    Address(name: "Niles K", imageURL: "nilesk", address: "45 King St."),
                    Address(name: "Ingrid G",  imageURL: "ingridg", address: "33 Union St.")

所以我想得到这个结果：（过滤的AddressArray）

---

1。您只需使用

for in-loop

和

过滤器即可获得预期值：

    for VIP in VIPArray
    {
        let result = AddressArray.filter({ $0.name == VIP["name"] })
        print(result)
    }

2.或者您可以使用
map
和
filter
的组合来获得期望值

    let result = VIPArray.map { (VIP) -> Address? in
        if let address = AddressArray.filter({ $0.name == VIP["name"] }).first
        {
                return address
        }
        return nil
    }
    print(result)

如果你还面临任何问题，请告诉我

struct Address {
    var name: String
    var imageURL: String
    var address: String
}

let VIPArray = [["name": "John B"], ["name": "Sara K"]]

let AddressArray = [Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
                    Address(name: "Dave H",  imageURL: "daveh", address: "1011 Victoria St.."),
                    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av."),
                    Address(name: "Niles K", imageURL: "nilesk", address: "45 King St."),
                    Address(name: "Ingrid G",  imageURL: "ingridg", address: "33 Union St.")]


var filtered = [Address]()

for element in VIPArray {
    for address in AddressArray {
        if element["name"] == address.name {
            filtered.append(address)
        }
    }
}

for record in filtered {
    print(record)
}

输出：

地址（名称：“约翰B”，图像URL：“约翰B”，地址：“缅因街178号”）

地址（名称：“sarak”，图像URL：“sarak”，地址：“枫叶大道279号”）

或：

这很简单，您的问题是完全开放的（“请为我编写我的全部代码”）。具体点。哪一部分你不知道怎么做？显示到目前为止的代码并解释问题所在。证明你做了一次诚实的尝试。
VIPArray
是数组数组还是字典数组？VIPArray是数组，而AddressArray是字典数组，这就是我被卡住的原因。马特，我尝试了太多不同的过滤解决方案，我都迷路了。没有什么对我有用，这就是为什么我没有发布任何东西。我搜索了所有可能的解决方案，其中大部分我都尝试过，但都没有找到。这是我最后的办法。对不起，您的
VIPArray
真的是
[[String]]
？您可以选择单击变量名进行检查。我也尝试了此操作，但我得到了相同的错误，即不能将“[String]”类型的值下标为“String”类型的索引什么是
VIPArray
和
AddressArray
？let result=VIPArray.map{（VIP）->Address？in if let Address=AddressArray.filter({$0.name==VIP[“name”]}。第一个{返回地址}返回零}打印（结果）确定。如果你的答案有效，请接受。祝你编码愉快
let VIPArray = [["name": "John B"], ["name": "Sara K"]]

struct Address {
    let name: String
    let imageURL: String
    let address: String
}

let addressArray = [Address(name: "John B",  imageURL: "johnb", address: "178 Main St."),
                    Address(name: "Dave H",  imageURL: "daveh", address: "1011 Victoria St.."),
                    Address(name: "Sara K",  imageURL: "sarak", address: "279 Maple Av."),
                    Address(name: "Niles K", imageURL: "nilesk", address: "45 King St."),
                    Address(name: "Ingrid G",  imageURL: "ingridg", address: "33 Union St.")]

let myVips = addressArray.filter() {VIPArray.contains(["name":$0.name])}