Asp.net mvc 4 将模型转换为视图模型
我有一个模型给我的桌子主人Asp.net mvc 4 将模型转换为视图模型,asp.net-mvc-4,entity-framework-4,viewmodel,Asp.net Mvc 4,Entity Framework 4,Viewmodel,我有一个模型给我的桌子主人 namespace MyApp.Models { public partial class Owner { public int owner_id { get; set; } public string firstname { get; set; } public string lastname { get; set; } public string address { get; set;
namespace MyApp.Models
{
public partial class Owner
{
public int owner_id { get; set; }
public string firstname { get; set; }
public string lastname { get; set; }
public string address { get; set; }
public string city { get; set; }
public virtual User User { get; set; }
}
}
然后我有了我的ViewModel
public partial class OwnerData
{
public string firstname { get; set; }
public string lastname { get; set; }
public string address { get; set; }
}
我的控制器
public ActionResult Index()
{
//Create the object Owner based on the User Identity
Owner owner = CustomDbFunctions.GetUserEntity(User, db).Owner;
//New instance of the ViewModel
OwnerData ownerData = new OwnerData();
ownerData.lastname = owner.lastname;
ownerData.firstname = owner.firstname;
ownerData.address = owner.address;
return View(ownerData);
}
有一种更简单的方法可以将我的所有者
转换为所有者数据
,而无需重写我的对象的所有单个属性?您可以使用。这使它更简单,但我不确定这是您想要的
OwnerData ownerData = new OwnerData {
lastname = owner.lastname;
firstname = owner.firstname;
address = owner.address;
};
你可以用。这使它更简单,但我不确定这是你想要的
OwnerData ownerData = new OwnerData {
lastname = owner.lastname;
firstname = owner.firstname;
address = owner.address;
};
我想我用
Automapper
public ActionResult Index()
{
//Create the object Owner based on the User Identity
Owner owner = CustomDbFunctions.GetUserEntity(User, db).Owner;
Mapper.CreateMap<Owner, OwnerData>();
OwnerData ownerData = Mapper.Map<Owner, OwnerData>(owner);
return View(ownerData);
}
从package manager控制台。我想我用
Automapper
public ActionResult Index()
{
//Create the object Owner based on the User Identity
Owner owner = CustomDbFunctions.GetUserEntity(User, db).Owner;
Mapper.CreateMap<Owner, OwnerData>();
OwnerData ownerData = Mapper.Map<Owner, OwnerData>(owner);
return View(ownerData);
}
从package manager控制台。有一种方法,但肯定不简单。保持这种方式有一些工具使用“反射”,并通过匹配属性名称为您实现这一点。我现在会保持这种方式,但会在OwnerData中添加一个接受Owner对象的构造函数并执行此操作。@a Khudairy我想我通过使用Mapper.CreateMap()找到了一个使用Automapper的好方法;然后是OwnerData OwnerData=Mapper.Map(CustomDbFunctions.GetUserEntity(User,db.Owner);有一种方法,但肯定不简单。保持这种方式有一些工具使用“反射”,并通过匹配属性名称来为您实现这一点。我现在会保持这种方式,但会在OwnerData中添加一个接受Owner对象的构造函数并执行此操作。@a Khudairy我想我通过使用Mapper.CreateMap()找到了一个使用Automapper的好方法;然后是OwnerData OwnerData=Mapper.Map(CustomDbFunctions.GetUserEntity(User,db.Owner);最好在每次需要时编辑构造函数,而不是每次都这样做。最好在每次需要时编辑构造函数,而不是每次都这样做。Mapper.CreateMap调用应在每个应用程序域中进行一次。我们应该在应用程序_Start()方法中调用它。否则,每次调用Index()时都会调用它。CreateMap调用应在每个应用程序域中调用一次。我们应该在应用程序_Start()方法中调用它。否则,每次调用Index()时都会调用它