Assembly 在gas宏中自动生成xmm寄存器名称?
我想编写一个gas宏,根据参数n生成包含各种movdqu指令到xmm寄存器的代码Assembly 在gas宏中自动生成xmm寄存器名称?,assembly,x86,gnu-assembler,sse,Assembly,X86,Gnu Assembler,Sse,我想编写一个gas宏,根据参数n生成包含各种movdqu指令到xmm寄存器的代码 .macro xxmov n, p1 .if (\n == 1) xor %eax, %eax .endif .if (\n - 1) xxmov (\n - 1), \p1 .endif movdqu ((\n - 1)*0x10)(\p1
.macro xxmov n, p1
.if (\n == 1)
xor %eax, %eax
.endif
.if (\n - 1)
xxmov (\n - 1), \p1
.endif
movdqu ((\n - 1)*0x10)(\p1), %xmm0
.endm
xxmov 14, %rsi
编译后,反汇编的代码
0000000000000000 <.text>:
0: 31 c0 xor %eax,%eax
2: f3 0f 6f 06 movdqu (%rsi),%xmm0
6: f3 0f 6f 46 10 movdqu 0x10(%rsi),%xmm0
b: f3 0f 6f 46 20 movdqu 0x20(%rsi),%xmm0
10: f3 0f 6f 46 30 movdqu 0x30(%rsi),%xmm0
15: f3 0f 6f 46 40 movdqu 0x40(%rsi),%xmm0
1a: f3 0f 6f 46 50 movdqu 0x50(%rsi),%xmm0
1f: f3 0f 6f 46 60 movdqu 0x60(%rsi),%xmm0
24: f3 0f 6f 46 70 movdqu 0x70(%rsi),%xmm0
29: f3 0f 6f 86 80 00 00 movdqu 0x80(%rsi),%xmm0
30: 00
31: f3 0f 6f 86 90 00 00 movdqu 0x90(%rsi),%xmm0
38: 00
39: f3 0f 6f 86 a0 00 00 movdqu 0xa0(%rsi),%xmm0
40: 00
41: f3 0f 6f 86 b0 00 00 movdqu 0xb0(%rsi),%xmm0
48: 00
49: f3 0f 6f 86 c0 00 00 movdqu 0xc0(%rsi),%xmm0
50: 00
51: f3 0f 6f 86 d0 00 00 movdqu 0xd0(%rsi),%xmm0
58: 00
那么,我是否可以将宏操作为xmm寄存器名(从%xmm0到%xmm_{n-1})?我已经尝试了中提到的\@(%xmm \@)。然而,它并没有很好地工作,因为我想多次使用这个宏,而\@似乎是单调递增的 与其倒计时,不如保留一个变量进行倒计时?像这样:
.macro xxmov n, p1, cnt=0
.if (\cnt == 0)
xor %eax, %eax
.endif
.if (\cnt != \n)
movdqu \@*0x10(\p1), %xmm\@
xxmov \n, \p1, (\cnt + 1)
.endif
.endm
xxmov 14, %rsi
由此产生:
0000000000000000 <.text>:
0: 31 c0 xor %eax,%eax
2: f3 0f 6f 06 movdqu (%rsi),%xmm0
6: f3 0f 6f 4e 10 movdqu 0x10(%rsi),%xmm1
b: f3 0f 6f 56 20 movdqu 0x20(%rsi),%xmm2
10: f3 0f 6f 5e 30 movdqu 0x30(%rsi),%xmm3
15: f3 0f 6f 66 40 movdqu 0x40(%rsi),%xmm4
1a: f3 0f 6f 6e 50 movdqu 0x50(%rsi),%xmm5
1f: f3 0f 6f 76 60 movdqu 0x60(%rsi),%xmm6
24: f3 0f 6f 7e 70 movdqu 0x70(%rsi),%xmm7
29: f3 44 0f 6f 86 80 00 00 00 movdqu 0x80(%rsi),%xmm8
32: f3 44 0f 6f 8e 90 00 00 00 movdqu 0x90(%rsi),%xmm9
3b: f3 44 0f 6f 96 a0 00 00 00 movdqu 0xa0(%rsi),%xmm10
44: f3 44 0f 6f 9e b0 00 00 00 movdqu 0xb0(%rsi),%xmm11
4d: f3 44 0f 6f a6 c0 00 00 00 movdqu 0xc0(%rsi),%xmm12
56: f3 44 0f 6f ae d0 00 00 00 movdqu 0xd0(%rsi),%xmm13
是的,.altmacro在这里确实有帮助。谢谢
0000000000000000 <.text>:
0: 31 c0 xor %eax,%eax
2: f3 0f 6f 06 movdqu (%rsi),%xmm0
6: f3 0f 6f 4e 10 movdqu 0x10(%rsi),%xmm1
b: f3 0f 6f 56 20 movdqu 0x20(%rsi),%xmm2
10: f3 0f 6f 5e 30 movdqu 0x30(%rsi),%xmm3
15: f3 0f 6f 66 40 movdqu 0x40(%rsi),%xmm4
1a: f3 0f 6f 6e 50 movdqu 0x50(%rsi),%xmm5
1f: f3 0f 6f 76 60 movdqu 0x60(%rsi),%xmm6
24: f3 0f 6f 7e 70 movdqu 0x70(%rsi),%xmm7
29: f3 44 0f 6f 86 80 00 00 00 movdqu 0x80(%rsi),%xmm8
32: f3 44 0f 6f 8e 90 00 00 00 movdqu 0x90(%rsi),%xmm9
3b: f3 44 0f 6f 96 a0 00 00 00 movdqu 0xa0(%rsi),%xmm10
44: f3 44 0f 6f 9e b0 00 00 00 movdqu 0xb0(%rsi),%xmm11
4d: f3 44 0f 6f a6 c0 00 00 00 movdqu 0xc0(%rsi),%xmm12
56: f3 44 0f 6f ae d0 00 00 00 movdqu 0xd0(%rsi),%xmm13
.altmacro
.macro xxmov n, p
.if (\n == 1)
xor %eax, %eax
.endif
.if (\n > 1)
xxmov %(\n - 1), \p
.endif
movdqu (\n - 1)*0x10 (%\p) , %xmm\n
.endm
xxmov 4, rsi
xxmov 14, rsi