Audio 如何反转滑块的ln幂函数?

Audio 如何反转滑块的ln幂函数?,audio,slider,mixer,natural-logarithm,math-functions,Audio,Slider,Mixer,Natural Logarithm,Math Functions,我能从Helmut Sennewald的LTSpice电位计代码中翻译出来。 但数学不是我的专长,所以我不确定是否有可能逆转这一点,所以如果给定一点的话 ln段算法将返回原始直线段上的相应值。目前,我最天真的解决方案是扫描东西以获得答案。这是原始的工作转发代码 //power function slider public float projectOntoSegment(float val, float min, float max) { //val is location as p

我能从Helmut Sennewald的LTSpice电位计代码中翻译出来。 但数学不是我的专长,所以我不确定是否有可能逆转这一点,所以如果给定一点的话 ln段算法将返回原始直线段上的相应值。目前,我最天真的解决方案是扫描东西以获得答案。这是原始的工作转发代码

//power function slider 
public float projectOntoSegment(float val, float min, float max) {

    //val is location as percentage on segment
    float range = max - min;
    float tap_point = 0.2f;//knee point as percentage
    float tap_val = range * 0.05f; //how much at knee:lets say 5% of scale
    double exp = Math.log(tap_val / range) / Math.log(tap_point);
    double ratio = Math.pow(val, exp);
    float eff_val = min + (float) (range * ratio);

    //eff_val = min + (range*val);//linear

    return eff_val;
}

我找到了解决办法的帮助下,一些stackoverflow和运气。为什么需要这样做?因为在对数滑块的初始化阶段需要它。以下是方法和示例使用。用户给出的初始值是对数刻度。它仍然只是想要的价值,而不是真实的价值。要获得有效值,所需值必须首先在滑块上反向映射为等效线性值,然后反馈到正向对数映射中。这将产生良好且平滑的滑块体验

//ln power log
public float projectOntoLogCurve(float input, float min, float max, float kneePoint, float kneeMount) {

    //input is location as percentage on segment
    float range = max - min;
    double exp = Math.log(kneeMount) / Math.log(kneePoint);
    double ratio = Math.pow(input, exp);
    float output = min + (float) (range * ratio);

    return output;
}

//**********************************************
//reverse ln power log
public float projectBackFromLogCurve(float ln_input, float min, float max, float kneePoint, float kneeMount) {

    //ln_input is logaritmic location  on log curve
    float range = max - min;
    float z = (ln_input - min) / range;
    double exp = Math.log(kneeMount) / Math.log(kneePoint);
    float output = (float) Math.pow(z, 1.0 / exp);
    return output;// projection from log curve to linear curve
}
使用类似于:

    float min = -20.0f;
    float max = 100.0f;
    float def_val = 42.0f;
    float knee_point = 0.2f; //choose point as percentage on slider
    float knee_mount = 0.05f; //choose level value at that point
    float initVal = projectBackFromLogCurve(def_val, min, max, knee_point, knee_mount);
    this.value = initVal;
    float start = projectOntoLogCurve(this.value, min, max, knee_point, knee_mount);
    //now you have valid init value for slider
    setEffectiveValue(start);