在awk中打印字符串值会导致错误

这是我的密码

fatal: not enough arguments to satisfy format string
    `%s SPT=80'
     ^ ran out for this one

---

问题是

awk

的

printf

命令中缺少逗号：

Dec 26 09:17:51 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=313 TOS=0x00 PREC=0x00 TTL=64 ID=59334 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK PSH URGP=0 
Dec 26 09:17:52 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=1440 TOS=0x00 PREC=0x00 TTL=64 ID=47303 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK URGP=0 
Dec 26 09:17:52 localhost kernel: IN=eth0 OUT= MAC=00:10:c6:a8:da:68:00:90:7f:9c:50:5a:08:00 SRC=198.252.206.16 DST=10.128.1.225 LEN=1440 TOS=0x00 PREC=0x00 TTL=64 ID=47559 PROTO=TCP SPT=80 DPT=56506 WINDOW=46535 RES=0x00 ACK URGP=0 

引述:

一个简单的

printf

语句如下所示：

awk -v i=h -v j=17 'FNR == 2 {printf "%s ", $j}' newiptables.log
                                          ^
                                          |== This is needed

密切相关的问题：。不是完全重复，而是相同的数据流。

awk -v i=h -v j=17 'FNR == 2 {printf "%s ", $j}' newiptables.log
                                          ^
                                          |== This is needed

 printf format, item1, item2, ...