Azure 从JSON复杂类型获取数据的U-SQL脚本出现语法错误
这是我的输入JSON文件Azure 从JSON复杂类型获取数据的U-SQL脚本出现语法错误,azure,azure-data-lake,u-sql,Azure,Azure Data Lake,U Sql,这是我的输入JSON文件 [ { "Tag": "STACK007", "data": [ { "item": "UNIFY109", "timestamp": "2018-08-27T17:28:51.8490000Z", "jsonVersion": 1, "messageType": 1, "velocity": 709 } ], "EventProc
[
{
"Tag": "STACK007",
"data": [
{
"item": "UNIFY109",
"timestamp": "2018-08-27T17:28:51.8490000Z",
"jsonVersion": 1,
"messageType": 1,
"velocity": 709
}
],
"EventProcessedUtcTime": "2018-08-27T17:36:17.5519639Z",
"EventEnqueuedUtcTime": "2018-08-27T17:28:52.0010000Z"
}
]
我正在尝试将此输入JSON文件转换为CSV。这是我的U-SQL脚本
REFERENCE ASSEMBLY [Newtonsoft.Json];
REFERENCE ASSEMBLY [Microsoft.Analytics.Samples.Formats];
USING Microsoft.Analytics.Samples.Formats.Json;
DECLARE @input string = @"/demodata/logs/2018/08/input.json";
@json =
EXTRACT
Tag string,
EventProcessedUtcTime DateTime,
EventEnqueuedUtcTime DateTime,
JsonFunctions.JsonTuple(data) AS data
FROM @input
USING new JsonExtractor();
@result =
SELECT Tag,
address["velocity"]AS Velocity,
address["messageType"]AS MessageType,
address["timestamp"]AS Timestamp
FROM @json;
OUTPUT @result
TO "/output/demooutput.csv"
USING Outputters.Csv();
此脚本给了我一个语法错误,消息为“语法错误。应为下列之一:”
如何解决此问题?我发现之前已经回答了此问题:
@resultset =
EXTRACT
item string,
jsonversion int,
messageType int,
velocity float
FROM @input
USING new Microsoft.Analytics.Samples.Formats.Json.JsonExtractor("data[*]");
这是Michael Rys对这个问题的回答:
“实际上,JSONExtractor支持JSONPath中表示的rowpath参数,该参数使您能够识别要映射到行中的JSON对象或JSON数组项。因此,您可以使用一条语句从JSON文档中提取数据”“请在csv文件中定义所需的列。