PowerShell Azure IaaS为灾难恢复导出虚拟机、虚拟网络和存储
是否有人知道从Azure IaaS虚拟机实现中检索以下信息的方法和/或示例代码PowerShell Azure IaaS为灾难恢复导出虚拟机、虚拟网络和存储,azure,azure-storage,azure-virtual-machine,azure-powershell,azure-virtual-network,Azure,Azure Storage,Azure Virtual Machine,Azure Powershell,Azure Virtual Network,是否有人知道从Azure IaaS虚拟机实现中检索以下信息的方法和/或示例代码 按名称列出的关联虚拟网络-而不是子网；我已经可以得到它了，因为它对于订阅中的所有虚拟网络都不是唯一的，所以无法使用 VM连接的磁盘的存储帐户 作为问题的补充，我们正在尝试生成用于灾难恢复目的的XML，这将允许我们在主数据中心发生故障时在辅助数据中心上重建IaaS实现。我们已经设法检索了大部分（如果不是全部的话）我们需要的信息，但是找不到一种方法来从VM获取VNet（反之亦然）或VM磁盘的存储帐户/容器。在（2）上，您
<PersistentVMRole xmlns="http://schemas.microsoft.com/windowsazure" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<RoleName>name-of-the-virtual-machine</RoleName>
<RoleType>PersistentVMRole</RoleType>
<VMImage>name-of-vm-image</VMImage>
<MediaLocation>path-to-vhds</MediaLocation>
虚拟机的名称
PersistentVMRole
虚拟机映像的名称
vhds的路径
https://management.core.windows.net/<subscription-id>/services/hostedservices/<cloudservice-name>/deployments/<deployment-name>/roles/<role-name>
https://management.core.windows.net//services/hostedservices//deployments//roles/
-马特我将回答你问题的第二部分。使用powershell非常简单。假设vm名称为“testvm”，服务名称为“testservice”。Powershell以获取存储帐户名-
$disk = Get-AzureVM -ServiceName "testservice" –Name "testvm" | Get-AzureOSDisk
$mediaLink = $disk.MediaLink
$storageAccountName = $mediaLink.Host.Split('.')[0]
$storageAccountName
希望这能回答你的问题。我知道这个问题很老了，但没有完整的答案。我使用这个PowerShell脚本在单个订阅中将VM的XML数据收集到一个文件中。本质上，它获取所有信息，然后进行过滤
$VMs = Get-AzureRmVM
$NICs = Get-AzureRmNetworkInterface
$VNETs = Get-AzureRmVirtualNetwork
$AzureVMInventory = foreach ($VM in $VMs) {
$NIC = $NICs | Where { $_.Id -eq $VM.NetworkProfile.NetworkInterfaces.Id }
$Subnet = $VNETs.Subnets | Where { $_.Id -eq $NIC.IPConfigurations.Subnet.Id }
$VNET = $VNETs | Where {$_.Subnets.Id -eq $NIC.IPConfigurations.Subnet.Id}
$Property = [ordered]@{
Name = $VM.OSProfile.ComputerName
VMSize = $VM.HardwareProfile.VmSize
ResourceGroup = $VM.ResourceGroupName
OSDisk = $VM.StorageProfile.OsDisk.Vhd.Uri
DataDisk = $VM.StorageProfile.DataDisks.Vhd.Uri -join "#"
IPAddresses = $NIC.IpConfigurations.PrivateIPAddress
IPAllocationMethod = $NIC.IpConfigurations.PrivateIPAllocationMethod
nicName = $NIC.Name
vNet = $VNET.Name
Subnet = $Subnet.Name
Location = $NIC.Location
}
New-Object -TypeName PSObject -Property $Property
}
$XML = $AzureVMInventory | ConvertTo-Xml -Depth 99
# Inject XSLT processing into the XML
$ProcessInstruction = $XML.CreateProcessingInstruction('xml-stylesheet', 'type="text/xsl" href="style.xsl"')
$XML.InsertBefore($ProcessInstruction, $XML.DocumentElement)
$XML.Save("$PSScriptRoot\ProductionVMs.xml")
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="ISO-8859-1"/>
<xsl:template name="tokenizeString">
<!--passed template parameter -->
<xsl:param name="list"/>
<xsl:param name="delimiter"/>
<xsl:choose>
<xsl:when test="contains($list, $delimiter)">
<!-- get everything in front of the first delimiter -->
<xsl:value-of select="substring-before($list,$delimiter)"/>
<br />
<xsl:call-template name="tokenizeString">
<!-- store anything left in another variable -->
<xsl:with-param name="list" select="substring-after($list,$delimiter)"/>
<xsl:with-param name="delimiter" select="$delimiter"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:choose>
<xsl:when test="$list = ''">
<xsl:text/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$list"/>
<br />
</xsl:otherwise>
</xsl:choose>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="/">
<html>
<head>
<title>Azure Virtual Machines</title>
<link rel="stylesheet" href="style.css" type="text/css" />
</head>
<body>
<table>
<tr>
<th>Name</th>
<th>IP Addresses</th>
<th>IP Allocation Method</th>
<th>Virtual Network</th>
<th>Subnet</th>
<th>VMSize</th>
<th>Resource Group</th>
<th>Network Interface</th>
<th>Location</th>
<th>OS Disk</th>
<th>Data Disks</th>
</tr>
<xsl:for-each select="//Objects/Object">
<xsl:sort select="Property[@Name='Name']" order="ascending" data-type="text"/>
<xsl:variable name="datadisks" select="Property[@Name='DataDisk']"/>
<tr>
<td><xsl:value-of select="Property[@Name='Name']" /></td>
<td><xsl:value-of select="Property[@Name='IPAddresses']" /></td>
<td><xsl:value-of select="Property[@Name='IPAllocationMethod']" /></td>
<td><xsl:value-of select="Property[@Name='vNet']" /></td>
<td><xsl:value-of select="Property[@Name='Subnet']" /></td>
<td><xsl:value-of select="Property[@Name='VMSize']" /></td>
<td><xsl:value-of select="Property[@Name='ResourceGroup']" /></td>
<td><xsl:value-of select="Property[@Name='nicName']" /></td>
<!-- <td><xsl:value-of select="Property[@Name='Location']" /></td> -->
<xsl:choose>
<xsl:when test="Property[@Name='Location'] = 'northeurope'">
<td class="loc_ne">North Europe</td>
</xsl:when>
<xsl:when test="Property[@Name='Location'] = 'westeurope'">
<td class="loc_we">West Europe</td>
</xsl:when>
<xsl:otherwise>
<td class="loc_err">NOT EUROPE</td>
</xsl:otherwise>
</xsl:choose>
<td><xsl:value-of select="Property[@Name='OSDisk']" /></td>
<td>
<!-- <xsl:value-of select="Property[@Name='DataDisk']" /> -->
<xsl:choose>
<xsl:when test="boolean(Property[@Name='DataDisk'])">
<xsl:call-template name="tokenizeString">
<xsl:with-param name="list" select="Property[@Name='DataDisk']"/>
<xsl:with-param name="delimiter" select="'#'"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise/>
</xsl:choose>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
# Convert to HTML (if required)
$XSLT = New-Object System.Xml.Xsl.XslCompiledTransform;
$XSLT.Load("style.xsl");
$XSLT.Transform("VMs.xml", "VMs.html");
谢谢Matt-我想知道这是否是唯一的方法，但我希望返回的对象属性中会出现值，而不必手动从字符串的一部分提取它。我认为这将是目前唯一的选择。
# Convert to HTML (if required)
$XSLT = New-Object System.Xml.Xsl.XslCompiledTransform;
$XSLT.Load("style.xsl");
$XSLT.Transform("VMs.xml", "VMs.html");