Bash shell脚本不删除文件
我正在使用一些shell脚本编码,如下所示Bash shell脚本不删除文件,bash,shell,Bash,Shell,我正在使用一些shell脚本编码,如下所示 DBHOSTNAME=******** DBUSERNAME=***** DBPASSWORD=****** DBNAME=****** BACKUPFOLDER=$HOME/******* DELETEFILES=Y DAILYBACKUP=Y NUMDAILYBACKUPS=2 WEEKLYBACKUP=Y NUMWEEKLYBACKUPS=2 MONTHLYBACKUP=Y NUMMONTHLYBACKUPS=2 TODA
DBHOSTNAME=********
DBUSERNAME=*****
DBPASSWORD=******
DBNAME=******
BACKUPFOLDER=$HOME/*******
DELETEFILES=Y
DAILYBACKUP=Y
NUMDAILYBACKUPS=2
WEEKLYBACKUP=Y
NUMWEEKLYBACKUPS=2
MONTHLYBACKUP=Y
NUMMONTHLYBACKUPS=2
TODATE=$(date +%d)
TOMORROW=`date +%d -d "1 day"`
TODAY=$(date +%a)
MONTH=$(date +%B)
WEEK=$(date +%U)
if [ $TODATE -gt $TOMORROW ] && [ "$MONTHLYBACKUP" == "Y" ]
then
/usr/bin/mysqldump -h $DBHOSTNAME -u $DBUSERNAME -p$DBPASSWORD $DBNAME | gzip > $BACKUPFOLDER/$DBNAME'_'`date '+%m-%d-%Y'`'_'$MONTH.sql.gz
else
if [ "$TODAY" == "Sat" ] && [ "$WEEKLYBACKUP" == "Y" ]
then
/usr/bin/mysqldump -h $DBHOSTNAME -u $DBUSERNAME -p$DBPASSWORD $DBNAME | gzip > $BACKUPFOLDER/$DBNAME'_'`date '+%m-%d-%Y'`'_'Week$WEEK.sql.gz
else
if [ "$DAILYBACKUP" == "Y" ]
then
/usr/bin/mysqldump -h $DBHOSTNAME -u $DBUSERNAME -p$DBPASSWORD $DBNAME | gzip > $BACKUPFOLDER/$DBNAME'_'`date '+%m-%d-%Y'`'_'$TODAY.sql.gz
fi
fi
fi
if [ $DELETEFILES == Y ]
then
NUMWEEKLY=$[$NUMWEEKLYBACKUPS*7]
NUMMONTHLY=$[$NUMMONTHLYBACKUPS*31]
find $BACKUPFOLDER/*Sun.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
find $BACKUPFOLDER/*Mon.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
find $BACKUPFOLDER/*Tue.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
find $BACKUPFOLDER/*Wed.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
find $BACKUPFOLDER/*Thu.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
find $BACKUPFOLDER/*Fri.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
find $BACKUPFOLDER/*Sat.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
find $BACKUPFOLDER/*Week*.sql.gz -type f -mtime +$NUMWEEKLY -delete 2> /dev/null
find $BACKUPFOLDER/*January.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*February.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*March.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*April.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*May.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*June.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*July.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*August.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*September.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*October.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*November.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
find $BACKUPFOLDER/*December.sql.gz -type f -mtime +$NUMMONTHLY -delete 2> /dev/null
fi
这是工作正常,但不删除旧文件,我采取了以下地址
我需要的是3天的备份
像
今天文件在文件夹中
03/01/2017
04/01/2017
2017年1月5日
明天应该是
04/01/2017
05/01/2017
2017年1月6日
它应该删除3jan文件除了评论者所说的,我认为一个关键问题是您的
find
命令。例如,您有:
find $BACKUPFOLDER/*Sun.sql.gz -type f -mtime +$NUMDAILYBACKUPS -delete 2> /dev/null
但这应该是正确的
find "$BACKUPFOLDER" -name '*Sun.sql.gz' -type f -mtime "+$NUMDAILYBACKUPS" -delete
使用find
时,分别列出路径(“$BACKUPFOLDER”
)和文件名(-name'*Sun.sql.gz'
)。您还可以单引号引用文件名,以防止shell扩展它们
调试时,不要使用
2>/dev/null
。这将丢弃错误消息,否则可能会对解决问题有所帮助:)。首先,不要使用双重相等的==
,只放置一个相等的=
。在带有多个语句的条件句上使用double[[
和]
,我的意思是当您使用&&
时。例如:if[[$TODATE-gt$tomory]]&[$MONTHLYBACKUP=“Y”]]
或if[[$TODATE-gt$tomory&&“$MONTHLYBACKUP”=“Y”]]
@OscarAkaElvis如果您选择使用[
,您可以在单个命令中使用&
,。使用$(…)
而不是$[…]
。后者已经被弃用了几十年。是的,你也可以。注释编辑。我也发布了这篇文章,但从技术上讲,路径可以是文件名,而不仅仅是目录。(在这种情况下,你让shell通过globbing找到大多数候选文件;find
只是通过mtime
对它们进行过滤)。