bash curl获取请求原始头

bash curl获取请求原始头,bash,curl,get,request,Bash,Curl,Get,Request,你好,我正在尝试通过CURL发出以下GET请求 GET http://localhost:80/ HTTP/1.1 Host: localhost Proxy-Connection: keep-alive User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US) AppleWebKit/534.16 (KHTML, like Gecko) Chrome/10.0.648.204 Safari/534.16 Accept: ap

你好,我正在尝试通过CURL发出以下GET请求

GET http://localhost:80/ HTTP/1.1

Host: localhost

Proxy-Connection: keep-alive

User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US) AppleWebKit/534.16 (KHTML, like Gecko) Chrome/10.0.648.204 Safari/534.16

Accept: application/xml,application/xhtml+xml,text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5

Accept-Encoding: gzip,deflate,sdch

Accept-Language: en-GB,en-US;q=0.8,en;q=0.6

Accept-Charset: ISO-8859-1,utf-8;q=0.7,*;q=0.3
所以我尝试了
curl-h“Host:localhost”localhost

但是它不起作用,任何想法我在这里哪里出了问题?

它是
-H
不是
-H

curl -H "Host:localhost" localhost