Bash 将文件的每个字段相乘

我必须制作一个bash脚本，将文件的每个第一个字段乘以10

示例（number.csv）：

我想展示：

"10","0","Test1","2016-03-31 15:34:50",\N,\N,"2016-03-31 15:34:58","2","2","2","1","test","3","3","3","0","1","0",\N,"1","0","0",\N,\N,"0","0","0","0","8","0","0","0","0"
"20","0","Test1","2016-03-31 15:34:50",\N,\N,"2016-03-31 15:34:58","2","2","2","1","test","3","3","3","0","1","0",\N,"1","0","0",\N,\N,"0","0","0","0","8","0","0","0","0"
"30","0","Test1","2016-03-31 15:34:50",\N,\N,"2016-03-31 15:34:58","2","2","2","1","test","3","3","3","0","1","0",\N,"1","0","0",\N,\N,"0","0","0","0","8","0","0","0","0"
...

我该怎么做？

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谢谢

如果您不想使用awk或Perl及其应用程序，您可以尝试一个简单的

sed 's/",/0",/'

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你可能想展示你目前为止的脚本，以缩小可能的答案数量，试图把问题从“暂停”中解救出来。它很有效，非常感谢！如果我只想乘以第二个字段，我会找到解决方案：awk-F，-v OFS=，“$2*=10{print”\”“$1”\”，“\”“$2”\”，“\”“$3”\”，“\”“$4”\”number.csv

sed 's/",/0",/'