Bash AWK脚本文件：组合2个命令

我想合并这两个命令：

命令1：

`BEGIN {
    ip = ARGV[2]
    split(ip, octets, ".")
    for (i = 1; i <= 4; i++) {
        dec += octets[i] * 256 ** (4 - i)
    }
    printf("%i\n", dec)
}`

要读取的文件：

"16777216","16777471","apnic","1313020800","AU","AUS","Australia"
"16777472","16777727","apnic","1302739200","CN","CHN","China"
"16777728","16778239","apnic","1302739200","CN","CHN","China"
"16778240","16779263","apnic","1302566400","AU","AUS","Australia"
"16779264","16781311","apnic","1302566400","CN","CHN","China"

第一个命令用于将IPV4地址转换为十进制，第二个命令用于搜索.csv文件中的十进制

因此，我想使用如下命令：

---

awk-f script.awk fileToRead.csv 10101100.00010000.1111111 0.0000000 1

将两个文件连接起来几乎可以实现您想要的功能（在对ARGV[2]进行重映射之后，因此它不会被视为文件）：

---

只是想把它整理一下。

谢谢！！！这正是我需要的。我不知道我们可以收拾argv.：）好你可以，但不是真的。我的意思是，您可以删除它或将其设置为null，然后脚本主体将跳过它，但是如果您在结尾部分循环使用ARGV，那么仍然会有一个null字符串条目。你知道你可以省略整个

END

部分，对吗？我不确定你是不是因为认为你必须拥有它才在里面打印东西。当然，BEGIN也是这样，但实际上您正在使用它。您发布了示例输入，但在给定该输入和您提供的命令的情况下忘记添加预期输出。

"16777216","16777471","apnic","1313020800","AU","AUS","Australia"
"16777472","16777727","apnic","1302739200","CN","CHN","China"
"16777728","16778239","apnic","1302739200","CN","CHN","China"
"16778240","16779263","apnic","1302566400","AU","AUS","Australia"
"16779264","16781311","apnic","1302566400","CN","CHN","China"

BEGIN {
    ip = ARGV[2]
    split(ip, octets, ".")
    for (i = 1; i <= 4; i++) {
        dec += octets[i] * 256 ** (4 - i)
    }
    ARGV[2] = ""
    ARGC--
}

BEGIN{
    FS=",";
}
{
    if ($4 == dec){
        print $7;
    }
}
END {
    print "END";
}

BEGIN {
    split(ip, octets, /[.]/)
    for (i = 1; i <= 4; i++) {
        dec += octets[i] * 256 ** (4 - i)
    }
    FS=","
}
$4 == dec {
    print $7
}
END {
    print "END"
}

awk -v 10101100.00010000.11111110.00000001 -f script.awk fileToRead.csv