Bash 将以前的文件和新文件合并在一起，并将mv转换为临时文件。

我正在努力做到以下几点：

set -x

substring()
{
    VAR=$1
    OFFSET=$2
    LENGTH=$3
    RET_VAL=${VAR:$OFFSET:$LENGTH}
}

# $1 filename

# Change to PF Gazetteer directory
cd $CARRIER_PF_UPDATES_DIR

LOG=log.txt
DownloadedFile=$1
OldFile=
DATE=$(date +"%Y-%m-%d-%H:%M:%S")
RET=0

if [ "${2+1}" == "1" ]
then
    echo "Date: " $DATE > $LOG
    echo "filename: " $DownloadedFile >> $LOG
fi

substring ${DownloadedFile} -3 3
extension=$RET_VAL
old_ext=$((${extension}+1))
substring ${DownloadedFile} 0 9
echo $RET_VAL
oldFile="${RET_VAL}${old_ext}"
#oldFile=`printf  "%02d" ${RET_VAL}`
#printf -v oldFile %02d "$RET_VAL"
#printf -v oldFile %02d "$((10#$RET_VAL - 1))"
extension=${1##*.}
printf -v decr "%s.%0${#extension}d" "${1%.*}" "$((10#$extension - 1))" \
&& cat -- "$decr" "$1" > temp \
&& rm -- "$decr" \
&& mv -- temp "$1"
oldFile="${oldFile}${old_ext}"
echo $oldFile

# move any temporary files if they exist
mv "${DownloadedFile}~" ${DownloadedFile}

# check to see if we got a file
result=$(grep 226 run.ilog)


if [ "${2+1}" == "1" ]
then
    echo "grep found: " $result >> $LOG
fi

if [ -e "${DownloadedFile}" ]
then
   #add back onto filename
   #store back onto var = $OldFile
   #Check if OldFile exist
   #Cat files together and - Cat oldFile DownloadedFile > tempFile
echo ""
fi

if [ "$result" == "" ]
then
     # File not found
     RET=100
else
     RET=10
     # START F4202
     sorted=$(sort -t'+' -k7 ${fileName} > ${fileName}.sorted)
     if [ -e "${fileName}.sorted" ]
     then
        mv "${fileName}" "unsorted/${fileName}.unsorted"
        mv "${fileName}.sorted" ${fileName}
     fi
     # END F4202
fi

if [ "${2+1}" == "1" ]
then
    echo "script ret: " $RET >> $LOG
fi

exit $RET

获取上一个文件名（如果存在）-我已经这样做了 将这两个文件分类为临时文件，即filename.002、filename.003>>临时文件 mv下载文件到某个地方，或者删除它 mv temp以更正文件名 我已经做了以下工作：

set -x

substring()
{
    VAR=$1
    OFFSET=$2
    LENGTH=$3
    RET_VAL=${VAR:$OFFSET:$LENGTH}
}

# $1 filename

# Change to PF Gazetteer directory
cd $CARRIER_PF_UPDATES_DIR

LOG=log.txt
DownloadedFile=$1
OldFile=
DATE=$(date +"%Y-%m-%d-%H:%M:%S")
RET=0

if [ "${2+1}" == "1" ]
then
    echo "Date: " $DATE > $LOG
    echo "filename: " $DownloadedFile >> $LOG
fi

substring ${DownloadedFile} -3 3
extension=$RET_VAL
old_ext=$((${extension}+1))
substring ${DownloadedFile} 0 9
echo $RET_VAL
oldFile="${RET_VAL}${old_ext}"
#oldFile=`printf  "%02d" ${RET_VAL}`
#printf -v oldFile %02d "$RET_VAL"
#printf -v oldFile %02d "$((10#$RET_VAL - 1))"
extension=${1##*.}
printf -v decr "%s.%0${#extension}d" "${1%.*}" "$((10#$extension - 1))" \
&& cat -- "$decr" "$1" > temp \
&& rm -- "$decr" \
&& mv -- temp "$1"
oldFile="${oldFile}${old_ext}"
echo $oldFile

# move any temporary files if they exist
mv "${DownloadedFile}~" ${DownloadedFile}

# check to see if we got a file
result=$(grep 226 run.ilog)


if [ "${2+1}" == "1" ]
then
    echo "grep found: " $result >> $LOG
fi

if [ -e "${DownloadedFile}" ]
then
   #add back onto filename
   #store back onto var = $OldFile
   #Check if OldFile exist
   #Cat files together and - Cat oldFile DownloadedFile > tempFile
echo ""
fi

if [ "$result" == "" ]
then
     # File not found
     RET=100
else
     RET=10
     # START F4202
     sorted=$(sort -t'+' -k7 ${fileName} > ${fileName}.sorted)
     if [ -e "${fileName}.sorted" ]
     then
        mv "${fileName}" "unsorted/${fileName}.unsorted"
        mv "${fileName}.sorted" ${fileName}
     fi
     # END F4202
fi

if [ "${2+1}" == "1" ]
then
    echo "script ret: " $RET >> $LOG
fi

exit $RET

但是，当我运行此命令时，当我键入FileName.005时，我会在终端中收到以下消息

应该发生的是 1我键入一个文件名，即Filename.005。它检查文件名是否存在

2从文件名为Filename.004的文件中获取递减的旧文件

3然后将内容汇总成一个文件

我做得对吗。请原谅我犯的任何错误，因为我对bash还不熟悉

问题是${DownloadedFile}~不存在，因此移动失败。在移动之前，您应该首先检查它是否存在

[ -e "${DownloadedFile}~" ] && mv "${DownloadedFile}~" "${DownloadedFile}"

---

好的，如果它检查移动是否存在，应该会清除其中一些错误？这确实有效，但是，我仍然保留了剩余的：cat:FileName.004:没有这样的文件或目录cat:FileName.005:没有这样的文件或目录FileName.005和FileName.004存在吗？当我运行bash文件时，我键入FilenName.005并收到以下信息：错误显示FileName.005和FileName.004不存在。应该吗？