我想在bash脚本的输出中添加错误的含义
我有一个源文件，里面填充了这样的行我想在bash脚本的输出中添加错误的含义,bash,loops,awk,printf,echo,Bash,Loops,Awk,Printf,Echo,我有一个源文件，里面填充了这样的行 e9999=$"First named error has occurred" e1000=$"Second named error has occurred" e0000=$"Another named error has occurred" 我有一个脚本，它以这样的行输出结束。脚本是多个greps到一些sed，然后是更多greps Dec 03 22:15:49 uniqid c5bb3ed1d2110203e2850998f1008e92
e9999=$"First named error has occurred"
e1000=$"Second named error has occurred"
e0000=$"Another named error has occurred"
Dec 03 22:15:49 uniqid c5bb3ed1d2110203e2850998f1008e92 IP 0.0.0.0 email@email.fqdn StatusCode: 1000
Dec 04 07:53:12 uniqid 476ceb443a552012a1dd1e754d279018 IP 255.255.255.255 email@email.fqdn StatusCode: 9999
Dec 04 10:51:08 uniqid 4c27a6e016e8b5c0a659274d20c86e0c IP 192.168.0.1 email@email.fqdn StatusCode: 0000
#!/bin/bash
source ~/ondemandscripts/errorcodes
today=$(date "+%b %d")
yesterday=$(date -d "1 day ago" "+%b %d")
echo -e "\nChecking "/opt/app/app/logs/PHP_Debug_Log" for errors and users email address"
echo -e "\n"
if [ $# -lt 1 ]
then
echo -e "Designed for app\nUsage options:\n$0 all\n$0 today\n$0 yesterday\n$0 alluniq\n$0 todayuniq\n$0 yesterdayuniq\n"
exit 1;
fi
if [ $1 = "all" ]; then
grep -i 'statusCode' /opt/app/app/logs/PHP_Debug_Log | grep '1010\|1020\|2120\|2140\|2142\|2160\|2510\|2520\|2530\|2540\|2560\|3101\|3102\|3103\|3104\|3110\|3111\|3118\|3120\|3130\|3150\|3180\|3210\|3220\|3230\|3240\|3250\|3320\|3325\|3330\|3340\|3350\|3360\|3420\|3450\|3510\|3520\|3610\|3612\|3614\|3620\|3622\|3630\|3650\|3657\|3660\|3662' | sed 's/Comms.*<status>/ /' | sed 's/<\/statusCode>.*/ /' | sed 's/debug//'| sed 's/app//'| sed 's/>/ /' | sed 's/</ /' | sed 's/]/ /g' | sed 's/\[/ /g' | sed 's/reg_phase1.*result./ /' | sed 's/reg_phase1.*for / /' | grep -v "StatusCode: 7000" | grep 'email.com'
else
echo -e "Designed for app\nUsage options:\n$0 all\n$0 today\n$0 yesterday\n$0 alluniq\n$0 todayuniq\n$0 yesterdayuniq\n"
fi
基于这个问题，卷非常大，可能是行，等等。这意味着这里需要脚本引擎awk、Perl、Python等等。。。。不管怎样，逻辑都是一样的 预加载查找表以查找错误代码 对于每一行： 从第10列中查找错误代码 将错误测试附加到he行 使用awk时，假设查找表位于errors.txt中
awk -v LOOKUP=lookup.txt '
BEGIN {
# Read the errors.txt file into array x, using custom FS
FS="=\\$"
while ( (getline < LOOKUP) > 0 ) { x[$1] = substr($2, 2, length($2)-2) }
# Restore FS
FS=" "
}
{
print $0, x["e" $10] ;
}
' data.txt
这一点也不清楚。请用三件重要的事情编辑你的问题。第一个输入示例，第二个输出示例，第三个是您为解决自己的问题所付出的努力，请编辑您的问题，然后告诉我们。您解决问题的代码在哪里，您的问题在哪里？@EdMorton您能否分享在这种情况下会使getline陷入循环的具体输入？上述用法在案例C的“应用”部分中描述为合适的解决方案@EdMorton Good point。我已经更新了答案。不知何故，我错过了awk手册中的这一段，并假设结果为0/1。谢谢，终于有时间添加此内容，并根据需要进行操作
awk -v LOOKUP=lookup.txt '
BEGIN {
# Read the errors.txt file into array x, using custom FS
FS="=\\$"
while ( (getline < LOOKUP) > 0 ) { x[$1] = substr($2, 2, length($2)-2) }
# Restore FS
FS=" "
}
{
print $0, x["e" $10] ;
}
' data.txt