Batch file 如何通过findstr命令从文本文件中找到的行中仅获取最后5个数字？

我想从显示的txt文件输出中获取FindStr命令的最后5个数字

这是我的命令：

FindStr "lastServer" C:\Users\Defcon1\AppData\Roaming\.minecraft\.options.txt

显示输出的示例如下：

lastServer:111.111.111.111:53680

---

如何从输出行仅获取5个数字（IP地址和端口号），而不使用字符串

lastServer:

？

这是一项非常简单的任务，易于编码，例如：

@echo off
setlocal
set "OptionsFile=%APPDATA%\.minecraft\.options.txt"

rem Does the file exist at all?
if not exist "%OptionsFile%" (
    echo Error: File %OptionsFile% not found!
    goto EndBatch
)

rem Search for last server line in file and get IP address and port number.
set "IP_and_Port="
for /F "tokens=1* delims=:" %%I in ('%SystemRoot%\System32\findstr.exe "lastServer" "%OptionsFile%" 2^>nul') do set "IP_and_Port=%%J"

rem Was IP and port number found in file?
if "%IP_and_Port%" == "" (
    echo Error: Found in file %OptionsFile%
    echo        no line with string "lastServer" with an IP address and a port number!
    goto EndBatch
)

rem Output found data.
echo Found: %IP_and_Port%

:EndBatch
endlocal
pause

也可在根本不使用findstr实用程序的情况下工作：

@echo off
setlocal
set "OptionsFile=%APPDATA%\.minecraft\.options.txt"

rem Does the file exist at all?
if not exist "%OptionsFile%" (
    echo Error: File %OptionsFile% not found!
    goto EndBatch
)

rem Search for last server line in file and get IP address and port number.
for /F "usebackq tokens=1* delims=:" %%I in ("%OptionsFile%") do (
    if /I "%%I" == "lastServer" (
        set "IP_and_Port=%%J"
        goto DataFound
    )
)

echo Error: Found in file %OptionsFile%
echo        no line with string "lastServer" with an IP address and a port number!
goto EndBatch

rem Output found data.
:DataFound
echo Found: %IP_and_Port%

:EndBatch
endlocal
pause

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