C 我无法理解为什么不能正确显示扫描的信息

我想问题当然在于地址或指针，但我找不到它。有人能描述一下这个问题吗，或者如果有人愿意修复代码的话

我的问题是，它不会在提示时打印我输入的内容

#include <stdio.h>
#include <stdlib.h>

void getData(int* enterhour, int* enterminute, int* exitotalhour, int* exminute);
void rate(int exitotalhour, int exminute, int enterhour, int enterminute, int* totalhour, int* totalminute, int* round);
void charge(char* vehic, float* rate1, float* rate2, int enterhour);
void result(int* exitotalhour, int* exminute, int* enterhour, int* enterminute, int* totalhour, float* rate1, float* rate2, int* round, float* total);

int main(void)
{
    char vehic;
    int enterhour;
    int enterminute;
    int exitotalhour;
    int exminute;
    int totalhour;
    int totalminute;
    int round;

    float rate1;
    float rate2;
    float total;

    getData(&enterhour, &enterminute, &exitotalhour, &exminute);
    rate(exitotalhour, exminute, enterhour, enterminute, &totalhour, &totalminute, &round);
    charge(&vehic, &rate1, &rate2, enterhour);
    total= rate1 + rate2;
    result( &exitotalhour, &exminute, &enterhour, &enterminute, &totalhour, &rate1, &rate2, &round, &total);

    return 0;
}

void getData(int* enterhour, int* enterminute, int* exitotalhour, int* exminute)
{
    char v;

    printf("Enter c for car, b for bus, t for truck: ");
    scanf("%c", &v);
    printf("\nHour vehicle entered 0-24: ");
    scanf("%d", &enterhour);
    printf("\nMinute vehicle entered 0-60: ");
    scanf("%d", &enterminute);
    printf("\nHour vehicle exited 0-24: ");
    scanf("%d", &exitotalhour);
    printf("\nMinute vehicle exited 0-60: ");
    scanf("%d", &exminute);
    return;
}

void rate(int exitotalhour, int exminute, int enterhour, int enterminute, int* totalhour, int* totalminute, int* round)
{
    if(enterminute < exminute)
    {
        enterminute= enterminute + 60;
        exitotalhour= exitotalhour - 1;
    }

    *totalhour = enterhour - exitotalhour;
    *totalminute = enterminute - exminute;

    if ((*totalminute > 0 && *totalminute <= 60))
    {
        *totalhour = *totalhour + 1;
        *round = *totalminute * 0;
    }
    return;
}

void charge(char* vehic, float* rate1, float* rate2, int enterhour)
{
    switch (*vehic)
    {
        case 'c': if (enterhour <= 3)
        {
            *rate1 = 0.00;
            if (enterhour > 3)
            *rate2 = 1.50 * (float)(enterhour - 3);
        }
        break;

        case 't': if (enterhour <= 2)
        {
            *rate1 = 1.00 * (float)enterhour;
            if (enterhour > 2)
            *rate2 = 2.30 * (float)(enterhour - 2);
        }
        break;

        case 'b': if (enterhour <= 1)
        {
            *rate1 = 2.00 * (float)enterhour;
            if (enterhour > 1)
            *rate2 = 3.70 * (float)(enterhour - 1);
        }
        break;
    }
    return;
}

void result(int* exitotalhour, int* exminute, int* enterhour, int* enterminute, int* totalhour, float* rate1, float* rate2, int* round, float* total)
{
    printf("\n\t\t LOT CHARGE \t\t\n");
    printf("\nType of vehicle: Car or Bus or Truck");
    printf("\nTIME-IN\t\t %d:%d", enterhour, enterminute);
    printf("\nTIME-OUT\t\t %d:%d", exitotalhour, exminute);
    printf("\n\t\t\t --------");
    printf("\nPARKING TIME\t\t %d:%d", totalhour, round);
    printf("\n\t\t\t --------");
    *total= *rate1 + *rate2;
    printf("\nTOTAL CHARGE\t\t %4.2f\n\n", total);

    return;
}

#包括
#包括
void getData（int*enterhour，int*enterminute，int*exitotalhour，int*exminute）；
无效率（整数ExitTotalHour、整数exminute、整数enterhour、整数enterminute、整数*总小时、整数*总分钟、整数*轮）；
无效费用（字符*车辆、浮动*费率1、浮动*费率2、整数小时）；
作废结果（int*exitotalhour、int*exminute、int*enterhour、int*enterminute、int*totalhour、float*rate1、float*rate2、int*round、float*total）；
内部主（空）
{
汽车；
整小时；
整数分钟；
整小时；
int exminute；
整小时；
整数分钟；
整数轮；
浮动汇率1；
浮动汇率2；
浮动总额；
getData（&enterhour、&enterminute、&ExitTotalHour、&exminute）；
费率（ExitTotalHour、exminute、enterhour、enterminute和totalhour、totalminute和round）；
收费（&车辆，&费率1，&费率2，每小时）；
总计=费率1+费率2；
结果（&ExitTotalHour，&exminute，&enterhour，&enterminute，&totalhour，&rate1，&rate2，&round，&total）；
返回0；
}
void getData（int*enterhour，int*enterminute，int*exitotalhour，int*exminute）
{
char v；
printf（“输入c表示汽车，输入b表示公共汽车，输入t表示卡车：”）；
scanf（“%c”、&v）；
printf（“\n您的车辆输入0-24:”）；
scanf（“%d”、&enterhour）；
printf（“\n车辆输入0-60分钟：”）；
scanf（“%d”、&enterminute）；
printf（“\n您的车辆退出0-24:”）；
scanf（“%d”和&exitotalhour）；
printf（“\n车辆退出0-60分钟：”）；
扫描频率（“%d”和“exminute”）；
返回；
}
无效率（整数ExitTotalHour、整数exminute、整数enterhour、整数enterminute、整数*总小时、整数*总分钟、整数*轮）
{
如果（输入分钟<输出分钟）
{
enterminute=enterminute+60；
ExitTotalHour=ExitTotalHour-1；
}
*totalhour=enterhour-ExitTotalHour；
*totalminute=输入分钟-输出分钟；
如果（（*totalminute>0&&*totalminute，因为
result
的参数是
int*
，您不需要在
printf
中取消引用它们吗

printf("\nTIME-IN\t\t %d:%d", *enterhour, *enterminute);

由于
result
的参数是
int*
，您不需要在
printf
中取消引用它们吗

printf("\nTIME-IN\t\t %d:%d", *enterhour, *enterminute);

我认为您的问题在于此功能：

void getData(int* enterhour, int* enterminute, int* exitotalhour, int* exminute)
{
   char v;

   printf("Enter c for car, b for bus, t for truck: ");
   scanf("%c", &v);
   printf("\nHour vehicle entered 0-24: ");
   scanf("%d", &enterhour);
   printf("\nMinute vehicle entered 0-60: ");
   scanf("%d", &enterminute);
   printf("\nHour vehicle exited 0-24: ");
   scanf("%d", &exitotalhour);
   printf("\nMinute vehicle exited 0-60: ");
   scanf("%d", &exminute);
   return;
}

您正在将int指针传递到函数中，然后将这些指针的地址提供给
scanf
。您应该只传递指针本身：

void getData(int* enterhour, int* enterminute, int* exitotalhour, int* exminute)
{
   char v;

   printf("Enter c for car, b for bus, t for truck: ");
   scanf("%c", &v);
   printf("\nHour vehicle entered 0-24: ");
   scanf("%d", enterhour);
   printf("\nMinute vehicle entered 0-60: ");
   scanf("%d", enterminute);
   printf("\nHour vehicle exited 0-24: ");
   scanf("%d", exitotalhour);
   printf("\nMinute vehicle exited 0-60: ");
   scanf("%d", exminute);
   return;
}

我认为您的问题在于此功能：

void getData(int* enterhour, int* enterminute, int* exitotalhour, int* exminute)
{
   char v;

   printf("Enter c for car, b for bus, t for truck: ");
   scanf("%c", &v);
   printf("\nHour vehicle entered 0-24: ");
   scanf("%d", &enterhour);
   printf("\nMinute vehicle entered 0-60: ");
   scanf("%d", &enterminute);
   printf("\nHour vehicle exited 0-24: ");
   scanf("%d", &exitotalhour);
   printf("\nMinute vehicle exited 0-60: ");
   scanf("%d", &exminute);
   return;
}

您正在将int指针传递到函数中，然后将这些指针的地址提供给
scanf
。您应该只传递指针本身：

void getData(int* enterhour, int* enterminute, int* exitotalhour, int* exminute)
{
   char v;

   printf("Enter c for car, b for bus, t for truck: ");
   scanf("%c", &v);
   printf("\nHour vehicle entered 0-24: ");
   scanf("%d", enterhour);
   printf("\nMinute vehicle entered 0-60: ");
   scanf("%d", enterminute);
   printf("\nHour vehicle exited 0-24: ");
   scanf("%d", exitotalhour);
   printf("\nMinute vehicle exited 0-60: ");
   scanf("%d", exminute);
   return;
}

请缩进您的代码并直接在您的问题中发布。不要忘记去掉不相关的部分。（有利于调试以及向我们演示。）请缩进您的代码并直接在您的问题中发布。不要忘记去掉不相关的部分。（有利于调试以及向我们演示。）好的，这大大提高了输出，但是总成本计算没有正确显示，总时间计算似乎很奇怪。不过，谢谢，我会继续编辑指针！很高兴我能提供帮助，你也应该检查paislee发布的答案，看起来你的
printf
调用中也有错误。好吗已经极大地提高了输出，但是总成本计算没有正确显示，总时间计算似乎很奇怪。不过，谢谢，我会继续编辑指针！很高兴我能提供帮助，你也应该检查paislee发布的答案，看起来你的
printf
调用中也有错误。