C 使用SSE SIMD转换函数
我尝试在函数中使用sse simd指令计算值C 使用SSE SIMD转换函数,c,function,sse,simd,C,Function,Sse,Simd,我尝试在函数中使用sse simd指令计算值 double integrate (double from, double to,double* counter) { __m128d sum=_mm_setzero_pd(); __m128d val=_mm_setzero_pd(); __m128d width; __m128d fr=_mm_set1_pd(from); __m128d t=_mm_set1_pd(to); __m128
double integrate (double from, double to,double* counter)
{
__m128d sum=_mm_setzero_pd();
__m128d val=_mm_setzero_pd();
__m128d width;
__m128d fr=_mm_set1_pd(from);
__m128d t=_mm_set1_pd(to);
__m128d one=_mm_set1_pd(1.0);
__m128d a,b,c,step;
double result=0,i=0;
width=_mm_set1_pd((to-from)/1000);
while(i<1000){
step = _mm_loadu_pd(&counter[i]);
a = _mm_mul_pd(step,width);
b = _mm_add_pd(fr,a);
val = _mm_div_pd(one,b);
c = _mm_mul_pd(val,width);
sum = _mm_mul_pd(sum,c);
i=i+2;
}
for(int i=0; i<1000; i++) {
result += sum[i];
}
return result;
}
我试图做的是每次(例如r0:0 r1:1、r0:2、r1:3)将数组中名为counter(保存0到999的数字)的数字传递到步进向量2中,并计算其他值。我做错了什么?更改:
step = _mm_loadu_pd(&counter[i]);
致:
我可以问一下,既然编译器会为此生成一个很好的SSE代码,你们到底为什么要这么做?因为这是一个赋值
step = _mm_loadu_pd(&counter[i]);
step = _mm_loadu_pd(&counter[i]);
step = _mm_set1_pd(counter[i]);