使用函数的C语言科学计算器
我写了一个程序，它使用了大多数math.h库函数来创建一种科学计算器。然而，我没有得到期望的输出。我总是在输出的最后得到0.000000。请帮我找出我的错误，谢谢使用函数的C语言科学计算器,c,logic,calculator,C,Logic,Calculator,我写了一个程序，它使用了大多数math.h库函数来创建一种科学计算器。然而，我没有得到期望的输出。我总是在输出的最后得到0.000000。请帮我找出我的错误，谢谢 #include <stdio.h> #include <math.h> #define PI 3.14159265 float sine(float x); float cosine(float x); float tangent(float x); float sineh(float x); float
#include <stdio.h>
#include <math.h>
#define PI 3.14159265
float sine(float x);
float cosine(float x);
float tangent(float x);
float sineh(float x);
float cosineh(float x);
float tangenth(float x);
float logten(float x);
float squareroot(float x);
float exponent(float x);
float power(float x,float y);
int main()
{
int x,y,n,answer;
printf("What do you want to do?\n");
printf("1.sin 2.cos 3. tan 4. sinh 5.cosh 6.tanh 7.1og10 8. square root. 9.exponent 10.power.");
scanf ("%d",&n);
if (n<9 && n>0)
{
printf("\n What is x? ");
scanf("%f",&x);
switch (n)
{
case 1: answer = sine(x); break;
case 2: answer = cosine(x); break;
case 3: answer = tangent(x); break;
case 4: answer = sineh(x); break;
case 5: answer = cosineh(x); break;
case 6: answer = tangenth(x); break;
case 7: answer = logten(x); break;
case 8: answer = squareroot(x); break;
case 9: answer = exponent(x); break;
}
}
if (n==10)
{
printf("What is x and y?\n");
scanf("%f%f",&x,&y);
answer = power(x,y);
}
if (n>0 && n<11)
printf("%f",answer);
else
printf("Wrong input.\n");
return 0;
}
float sine(float x)
{
return (sin (x*PI/180));
}
float cosine(float x)
{
return (cos (x*PI/180));
}
float tangent(float x)
{
return (tan(x*PI/180));
}
float sineh(float x)
{
return (sinh(x));
}
float cosineh(float x)
{
return (sinh(x));
}
float tangenth(float x)
{
return (sinh(x));
}
float logten(float x)
{
return (log10(x));
}
float squareroot(float x)
{
return (sqrt(x));
}
float exponent(float x)
{
return(exp(x));
}
float power(float x, float y)
{
return (pow(x,y));
}
#包括
#包括
#定义PI 3.14159265
浮点正弦（浮点x）；
浮点余弦（浮点x）；
浮动切线（浮动x）；
浮子筋（浮子x）；
浮动余弦（浮动x）；
浮动切线H（浮动x）；
浮点数logten（浮点数x）；
浮点平方根（浮点x）；
浮点指数（浮点x）；
浮动功率（浮动x、浮动y）；
int main（）
{
int x，y，n，答案；
printf（“您想做什么？\n”）；
printf（“1.sin 2.cos 3.tan 4.sinh 5.cosh 6.tanh 7.1og10 8.平方根9.指数10.幂”）；
scanf（“%d”和“&n”）；
如果（n0）
{
printf（“\n x是什么？”）；
scanf（“%f”、&x）；
开关（n）
{
案例1：答案=正弦（x）；中断；
案例2：答案=余弦（x）；中断；
案例3：答案=切线（x）；中断；
案例4：答案=正弦（x）；中断；
案例5：答案=余弦（x）；中断；
案例6：答案=切线H（x）；断裂；
案例7：答案=logten（x）；中断；
案例8：答案=平方根（x）；中断；
案例9：答案=指数（x）；中断；
}
}
如果（n==10）
{
printf（“x和y是什么？\n”）；
scanf（“%f%f”、&x和&y）；
答案=功率（x，y）；
}
如果（n>0&&n您已将这四个变量声明为整数：
int x,y,n,answer;
但是n
是唯一一个您实际将其视为整数的变量。将x
、y
和answer
声明为float
：
int n;
float x, y, answer;
如果启用-Wall和-Wconversion，我会看到以下警告，如果您解决了这些警告，将解决您的问题：
foo.c:23:14: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f",&x);
~~ ^~
%d
foo.c:26:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 1: answer = sine(x); break;
~ ^~~~~~~
foo.c:27:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 2: answer = cosine(x); break;
~ ^~~~~~~~~
foo.c:28:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 3: answer = tangent(x); break;
~ ^~~~~~~~~~
foo.c:29:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 4: answer = sineh(x); break;
~ ^~~~~~~~
foo.c:30:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 5: answer = cosineh(x); break;
~ ^~~~~~~~~~
foo.c:31:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 6: answer = tangenth(x); break;
~ ^~~~~~~~~~~
foo.c:32:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 7: answer = logten(x); break;
~ ^~~~~~~~~
foo.c:33:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 8: answer = squareroot(x); break;
~ ^~~~~~~~~~~~~
foo.c:34:21: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
case 9: answer = exponent(x); break;
~ ^~~~~~~~~~~
foo.c:40:16: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f%f",&x,&y);
~~ ^~
%d
foo.c:40:19: warning: format specifies type 'float *' but the argument has type 'int *' [-Wformat]
scanf("%f%f",&x,&y);
~~ ^~
%d
foo.c:41:12: warning: implicit conversion turns floating-point number into integer: 'float' to 'int' [-Wconversion]
answer = power(x,y);
~ ^~~~~~~~~~
foo.c:44:15: warning: format specifies type 'double' but the argument has type 'int' [-Wformat]
printf("%f",answer);
~~ ^~~~~~
%d
foo.c:51:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sin (x*PI/180));
~~~~~~ ^~~~~~~~~~~~~~
foo.c:55:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (cos (x*PI/180));
~~~~~~ ^~~~~~~~~~~~~~
foo.c:59:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (tan(x*PI/180));
~~~~~~ ^~~~~~~~~~~~~
foo.c:63:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~ ^~~~~~~
foo.c:67:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~ ^~~~~~~
foo.c:71:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sinh(x));
~~~~~~ ^~~~~~~
foo.c:75:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (log10(x));
~~~~~~ ^~~~~~~~
foo.c:79:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (sqrt(x));
~~~~~~ ^~~~~~~
foo.c:83:9: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return(exp(x));
~~~~~~ ^~~~~~
foo.c:87:10: warning: implicit conversion loses floating-point precision: 'double' to 'float' [-Wconversion]
return (pow(x,y));
~~~~~~ ^~~~~~~~
24 warnings generated.
您将x
和其他变量声明为int
。请尝试声明为float
#include <stdio.h>
#include <math.h>
#include<conio.h>
#define PI 3.14159265
float sine(float x)
{
return (sin (x*PI/180));
}
float cosine(float x)
{
return (cos (x*PI/180));
}
float tangent(float x)
{
return (tan(x));
}
float sineh(float x)
{
return (sinh(x));
}
float cosineh(float x)
{
return (sinh(x));
}
float tangenth(float x)
{
return (sinh(x));
}
float logten(float x)
{
return (log10(x));
}
float squareroot(float x)
{
return (sqrt(x));
}
float exponent(float x)
{
return(exp(x));
}
float power(float x, float y)
{
return (pow(x,y));
}
int main(void)
{
int n;
float x,y,answer;
printf("What do you want to do?\n");
printf("1.sin 2.cos 3. tan 4. sinh 5.cosh 6.tanh 7.1og10 8. square root.
9.exponent 10.power.");
scanf ("%d",&n);
if (n<9 && n>0)
{
printf("\n What is x? ");
scanf("%f",&x);
switch (n)
{
case 1: answer = sine(x); break;
case 2: answer = cosine(x); break;
case 3: answer = tangent(x); break;
case 4: answer = sineh(x); break;
case 5: answer = cosineh(x); break;
case 6: answer = tangenth(x); break;
case 7: answer = logten(x); break;
case 8: answer = squareroot(x); break;
case 9: answer = exponent(x); break;
}
}
if (n==10)
{
printf("What is x and y?\n");
scanf("%f%f",&x,&y);
answer = power(x,y);
}
if (n>0 && n<11)
printf("%f",answer);
else
printf("Wrong input.\n");
getch();
return 0;
}
#包括
#包括
#定义PI 3.14159265
浮点正弦（浮点x）
{
回报率（sin（x*PI/180））；
}
浮点余弦（浮点x）
{
收益率（cos（x*PI/180））；
}
浮动切线（浮动x）
{
返回（tan（x））；
}
浮动正弦（浮动x）
{
返回（新罕布什尔州（x））；
}
浮动余弦（浮动x）
{
返回（新罕布什尔州（x））；
}
浮动切线H（浮动x）
{
返回（新罕布什尔州（x））；
}
浮动对数十（浮动x）
{
返回（log10（x））；
}
浮点平方根（浮点x）
{
返回（sqrt（x））；
}
浮点指数（浮点x）
{
返回（exp（x））；
}
浮动功率（浮动x、浮动y）
{
返回（功率（x，y））；
}
内部主（空）
{
int n；
浮动x，y，回答；
printf（“您想做什么？\n”）；
printf（“1.sin 2.cos 3.tan 4.sinh 5.cosh 6.tanh 7.1og10 8.平方根。
9.10.权力。”）；
scanf（“%d”和“&n”）；
如果（n0）
{
printf（“\n x是什么？”）；
scanf（“%f”、&x）；
开关（n）
{
案例1：答案=正弦（x）；中断；
案例2：答案=余弦（x）；中断；
案例3：答案=切线（x）；中断；
案例4：答案=正弦（x）；中断；
案例5：答案=余弦（x）；中断；
案例6：答案=切线H（x）；断裂；
案例7：答案=logten（x）；中断；
案例8：答案=平方根（x）；中断；
案例9：答案=指数（x）；中断；
}
}
如果（n==10）
{
printf（“x和y是什么？\n”）；
scanf（“%f%f”、&x和&y）；
答案=功率（x，y）；
}
如果（n>0&&n则问题在于格式说明符错误。请在scanf
语句中将所有%f
更改为%d