C 如何编写一个输入为n的程序，然后计算用户输入的n个数字的总和？

到目前为止，我已经写过：

#include<stdio.h>

int main()
{
    int n = 0, i = 0, sum = 0, a = 0;
    scanf("%d", &n);
    while (i <= n);
    {
        scanf("\n%d", &a);
        sum = sum + a;
        i++;
    }   
    printf("%d", sum);
}

例如，当我输入8时，它将不允许我添加任何其他数字

---

有什么问题吗？

而我当我@Shabnam时，你可以使用这个代码

#include <stdio.h>
int main()
{
  int n, sum = 0, c, value;

  printf("Enter the number of integers you want to add\n");
  scanf("%d", &n);

  printf("Enter %d integers\n",n);

  for (c = 1; c <= n; c++)
   {
     scanf("%d", &value);
     sum = sum + value;
   }

 printf("Sum of entered integers = %d\n",sum);

 return 0;
}

而我

#include <stdio.h>
int main()
{
  int n, sum = 0, c, value;

  printf("Enter the number of integers you want to add\n");
  scanf("%d", &n);

  printf("Enter %d integers\n",n);

  for (c = 1; c <= n; c++)
   {
     scanf("%d", &value);
     sum = sum + value;
   }

 printf("Sum of entered integers = %d\n",sum);

 return 0;
}