C 雇员结构
因此,我目前正在尝试学习C语言,完成一项任务,并且不断遇到相同的错误 上下文: 我要写一个有4个功能的程序- read_员工读取姓名、id和薪水,并将其存储在 然后返回的employee变量 打印员工读取员工结构,打印员工详细信息 employee\u total\u salary在一个参数中接受员工值数组 和另一个参数中数组的大小,并返回其所有参数的总和 员工索引搜索从员工结构中搜索ID 这是我被告知的密码:C 雇员结构,c,xcode,mingw,sublimetext3,C,Xcode,Mingw,Sublimetext3,因此,我目前正在尝试学习C语言,完成一项任务,并且不断遇到相同的错误 上下文: 我要写一个有4个功能的程序- read_员工读取姓名、id和薪水,并将其存储在 然后返回的employee变量 打印员工读取员工结构,打印员工详细信息 employee\u total\u salary在一个参数中接受员工值数组 和另一个参数中数组的大小,并返回其所有参数的总和 员工索引搜索从员工结构中搜索ID 这是我被告知的密码: 1: Print the message "-- Enter Array 1 Emp
1: Print the message "-- Enter Array 1 Employee Data –"
2: Loop i for each index of test_array1
3: Assign test_array1 at index i, the result of calling read_employee
4: Print the message '-- Enter Array 2 Employee Data --'
5: Loop i for each index of test_array2
6: Assign test_array2 at index i, the result of calling read_employee
7: Print the message "-- Test Array 1 --"
8: Loop i for each index of test_array1
9: Call print_employee, passing in test_array1 at index i
10: Print 'Total : ', employee_total_salary ( test_array1, 5 )
11: Print the message '-- Test Array 2 --'
12: Loop i for each index of test_array2
13: Call print_employee, passing in test_array2 at index i
14: Print "Total : ", employee_total_salary ( test_array2, 10)
15: Store in i, the employee_index_search passing in test_array1 , and the id 123 and
size 5
16: if something was found
17: Call print_employee passing in the located computer from testArray1
18: else
19: Print the message " array 1 does not contain a employee with id 123"
这是我写的代码:
#include <stdio.h>
struct employee{
char name[20];
int emp_id;
float salary;
}; struct employee e[];
void read_employee ()
{
int i = 0;
printf("%dEnter Employee Name: ", i);
scanf("%s", &e[i].name);
printf("Enter in ID: ");
scanf("%d", &e[i].emp_id);
printf("Enter in Salary: ");
scanf("%f", &e[i].salary);
i++;
}
void print_employee(){
for (int i = 0; i > 10; ++i)
{
if (e[i].salary < 4000)
{
printf("%s(%d):%f - Level A", e[i].name, e[i].emp_id, e[i].salary);
}
else if (e[i].salary > 5000)
{
printf("%s(%d):%f - Level B", e[i].name, e[i].emp_id, e[i].salary);
}
else
{
printf("%s(%d):%f", e[i].name, e[i].emp_id, e[i].salary);
}
}
}
//int employee_total_salary(){
//int total;
//sizeof(e.salary);
//total = sizeof(e.salary) + e.salary;
//return total;
//}
int employee_index_search(){
int *id;
int size = 5;
for (int i = 0; i < size; i++)
{
if (e[i].emp_id == id)
{
printf("%s(%d):%f", e[i].name, e[i].emp_id, e[i].salary);
}
else
{
printf("Array 1 does not contain an employee with ID 123");
return -1;
}
}
return 0;
}
int main(){
int test_array1[5];
int test_array2[10];
int i;
printf("\n-- Enter Array 1 Employee Data --\n");
for (int i = 0; i < 5; i++)
{
read_employee(&test_array1[i]);
}
printf("\n-- Enter Array 2 Employee Data --\n");
for (int i = 0; i < 10; i++)
{
read_employee(&test_array2[i]);
}
printf("-- Test Array 1 --\n");
for (int i = 0; i < 5; ++i)
{
print_employee(&test_array1[i]);
}
//printf("Total:");
//gets(employee_total_salary(test_array1, 5));
printf("-- Test Array 2 --\n");
for (int i = 0; i < 10; ++i)
{
print_employee(&test_array2[i]);
}
return 0;
//printf("Total:");
//gets(employee_total_salary(test_array2, 10));
//employeee_index_search();
}
有人能告诉我哪里出了问题吗?程序也不会调用print_employee并打印数组
我评论了其中一些,因为我想先尝试至少1-2个工作函数
scanf("%d", &read.emp_id);
你应该换成
scanf("%d", &read[i].emp_id);
当您通过时,读取为结构的数组
您还缺少main和employee_total_salary的参数括号read和p是指针类型!!!!print_employee没有返回值。欢迎使用StackOverflow。请坐飞机。请允许我推荐一个基本教程,一个演示编写函数的教程,你似乎错过了一些关于它们语法的细节。
scanf("%d", &read[i].emp_id);