Class 如何在UIWebview上获取类的超链接?
我可以通过以下代码获取该类的文本:Class 如何在UIWebview上获取类的超链接?,class,hyperlink,uiwebview,Class,Hyperlink,Uiwebview,我可以通过以下代码获取该类的文本: [webview stringByEvaluatingJavaScriptFromString:@"document.getElementsByClassName('normal fs16 bold c-red2')[0].innerHTML;"]; 但是我还需要获得这个类的链接。我刚刚解决了获取网站的所有链接并使用字符串的问题: [webView stringByEvaluatingJavaScriptFromString:@"var script = d
[webview stringByEvaluatingJavaScriptFromString:@"document.getElementsByClassName('normal fs16 bold c-red2')[0].innerHTML;"];
但是我还需要获得这个类的链接。我刚刚解决了获取网站的所有链接并使用字符串的问题:
[webView stringByEvaluatingJavaScriptFromString:@"var script = document.createElement('script');"
"script.type = 'text/javascript';"
"script.text = \"function getHyperlinks() { "
"var links = document.getElementsByTagName('a');"
"var allLinks = '';"
"for (var i = 0; i<links.length; i++) {"
"var link = links[i].href + '~' + links[i].text + '~' + links[i].title + ';';"
"allLinks += link;"
"} return allLinks;"
"}\";"
"document.getElementsByTagName('head')[0].appendChild(script);"];
NSString *html = [webView stringByEvaluatingJavaScriptFromString:
@"getHyperlinks();"];
[webView stringByEvaluatingJavaScriptFromString:@“var script=document.createElement('script')
“script.type='text/javascript'
“script.text=\”函数getHyperlinks(){”
“var links=document.getElementsByTagName('a')
“var allLinks=”
“对于(变量i=0;i