使用Clojure中的Specter删除嵌套值
假设我有这样一张Clojure地图:使用Clojure中的Specter删除嵌套值,clojure,specter,Clojure,Specter,假设我有这样一张Clojure地图: (def mymap {:a [1 2 3] :b {:c [] :d [1 2 3]}}) 我想要一个函数removeepties,它生成一个新的映射,其中(:b mymap)中具有空序列作为值的条目被删除。因此(删除清空mymap)将给出以下值: {:a [1 2 3] :b {:d [1 2 3]}} 有没有办法用Specter编写一个函数来实现这一点?到目前为止,我还没有找到一种使用Specter的过滤器的方法,因为当我测试过滤器时,它们似乎会两
(def mymap {:a [1 2 3] :b {:c [] :d [1 2 3]}})
我想要一个函数removeepties,它生成一个新的映射,其中(:b mymap)中具有空序列作为值的条目被删除。因此(删除清空mymap)将给出以下值:
{:a [1 2 3] :b {:d [1 2 3]}}
有没有办法用Specter编写一个函数来实现这一点?到目前为止,我还没有找到一种使用Specter的
过滤器的方法,因为当我测试过滤器时,它们似乎会两次接收每个映射条目(一次作为映射条目,一次作为两个长度向量),并且在这两个条目之间给出不同的结果似乎会导致问题。然而,我们不应该在任何可能出现的地方删除空序列,而应该将它们作为值的条目映射到其中
不过,我似乎确实得到了一种你可能仍然感兴趣的clojure.walk
方法
(ns nested-remove
(:require [com.rpl.specter :as s]
[clojure.walk :refer [postwalk]]))
(defn empty-seq-entry? [entry]
(and (map-entry? entry) (sequential? (val entry)) (empty? (val entry))))
(defn remove-empties [root]
(postwalk #(if (map? %) (into (empty %) (remove empty-seq-entry? %)) %) root))
(remove-empties mymap) ;;=> {:a [1 2 3], :b {:d [1 2 3]}}
虽然我对Specter不是很熟悉,但是除了postwalk
解决方案之外,您还可以使用tupelo.forest
解决这个问题。您确实需要将数据重新排列为Hiccup或Enlive格式,这样就很容易识别没有子节点的任何节点:
(ns tst.clj.core
(:use clj.core tupelo.test)
(:require
[tupelo.core :as t]
[tupelo.forest :as tf] ))
(t/refer-tupelo)
(defn hid->enlive [hid]
(tf/hiccup->enlive (tf/hid->hiccup hid)))
(defn empty-kids?
[path]
(let [hid (last path)
result (and (tf/node-hid? hid)
(empty? (grab :kids (tf/hid->tree hid))))]
result))
; delete any nodes without children
(dotest
(tf/with-forest (tf/new-forest)
(let [e0 {:tag :root
:attrs {}
:content [{:tag :a
:attrs {}
:content [1 2 3]}
{:tag :b
:attrs {}
:content [{:tag :c
:attrs {}
:content []}
{:tag :d
:attrs {}
:content [1 2 3]}
]}]}
root-hid (tf/add-tree-enlive e0)
empty-paths (tf/find-paths-with root-hid [:** :*] empty-kids?)
empty-hids (mapv last empty-paths)]
(is= (hid->enlive root-hid) ; This is the original tree structure (Enlive format)
{:tag :root,
:attrs {},
:content
[{:tag :a,
:attrs {},
:content
[{:tag :tupelo.forest/raw, :attrs {}, :content [1]}
{:tag :tupelo.forest/raw, :attrs {}, :content [2]}
{:tag :tupelo.forest/raw, :attrs {}, :content [3]}]}
{:tag :b,
:attrs {},
:content
[{:tag :c, :attrs {}, :content []}
{:tag :d,
:attrs {},
:content
[{:tag :tupelo.forest/raw, :attrs {}, :content [1]}
{:tag :tupelo.forest/raw, :attrs {}, :content [2]}
{:tag :tupelo.forest/raw, :attrs {}, :content [3]}]}]}]})
(apply tf/remove-hid empty-hids) ; remove the nodes with no child nodes
(is= (hid->enlive root-hid) ; this is the result (Enlive format)
{:tag :root,
:attrs {},
:content
[{:tag :a,
:attrs {},
:content
[{:tag :tupelo.forest/raw, :attrs {}, :content [1]}
{:tag :tupelo.forest/raw, :attrs {}, :content [2]}
{:tag :tupelo.forest/raw, :attrs {}, :content [3]}]}
{:tag :b,
:attrs {},
:content
[{:tag :d,
:attrs {},
:content
[{:tag :tupelo.forest/raw, :attrs {}, :content [1]}
{:tag :tupelo.forest/raw, :attrs {}, :content [2]}
{:tag :tupelo.forest/raw, :attrs {}, :content [3]}]}]}]})
(is= (tf/hid->hiccup root-hid) ; same result in Hiccup format
[:root
[:a
[:tupelo.forest/raw 1]
[:tupelo.forest/raw 2]
[:tupelo.forest/raw 3]]
[:b
[:d
[:tupelo.forest/raw 1]
[:tupelo.forest/raw 2]
[:tupelo.forest/raw 3]]]])
)))
我也不知道斯佩克特,但这在普通的clojure中是非常简单的
(defn remove-empties [m]
(reduce-kv (fn [acc k v]
(cond (map? v) (let [new-v (remove-empties v)]
(if (seq new-v)
(assoc acc k new-v)
acc))
(empty? v) acc
:else (assoc acc k v)))
(empty m), m))
警告:对于非常嵌套的数据结构,它可能会堆栈溢出。这是specter解决方案:
(update my-map :b (fn [b]
(apply dissoc b
(map key (filter (comp empty? val) b)))))
(ns myns.core
(:require
[com.rpl.specter :as spc]))
(def my-map
{:a [1 2 3]
:b {:c []
:d [1 2 3]}})
(defn my-function
[path data]
(let [pred #(and (vector? %) (empty? %))]
(spc/setval [path spc/MAP-VALS pred] spc/NONE data)))
;; (my-function [:b] my-map) => {:a [1 2 3]
;; :b {:d [1 2 3]}}
以下是如何使用:
在英语中,这表示“在:b
下,查找为空的所有映射值?
。将它们设置为无
,即删除它们。”假设我们只需要深入一层,而不需要像接受的答案那样递归搜索:
(setval [:b MAP-VALS empty?] NONE mymap)
一种完全递归的解决方案,可在任何级别删除映射中的空值
(def my-complex-map {:a [1] :b {:c [] :d [1 2 3] :e {:f "foo" :g []}}})
; declare recursive path that traverses map values
(declarepath DEEP-MAP-VALS)
(providepath DEEP-MAP-VALS (if-path map? [MAP-VALS DEEP-MAP-VALS] STAY))
(setval [DEEP-MAP-VALS empty?] NONE my-complex-map)
; => {:a [1], :b {:d [1 2 3, :e {:f "foo"}}}}
请参考上的wiki。Specter在香草解决方案中的强大威力
(def my-complex-map {:a [1] :b {:c [] :d [1 2 3] :e {:f "foo" :g []}}})
; declare recursive path that traverses map values
(declarepath DEEP-MAP-VALS)
(providepath DEEP-MAP-VALS (if-path map? [MAP-VALS DEEP-MAP-VALS] STAY))
(setval [DEEP-MAP-VALS empty?] NONE my-complex-map)
; => {:a [1], :b {:d [1 2 3, :e {:f "foo"}}}}