Cocoa touch 旋转OpenGL ES对象

Cocoa touch 旋转OpenGL ES对象,cocoa-touch,ios5,xcode4.2,opengl-es-2.0,Cocoa Touch,Ios5,Xcode4.2,Opengl Es 2.0,经过几个小时的努力,我终于能够画出一个物体,但当它旋转时,我被卡住了。我试图绕y轴旋转,但我似乎无法以任何方式使旋转平滑。它几乎是在跳来跳去。中间可能有一些不必要的部分,因此我使用了一个模板 - (void)update { float aspect = fabsf(self.view.bounds.size.width / self.view.bounds.size.height); GLKMatrix4 projectionMatrix = GLKMatrix4MakePer

经过几个小时的努力,我终于能够画出一个物体,但当它旋转时,我被卡住了。我试图绕y轴旋转,但我似乎无法以任何方式使旋转平滑。它几乎是在跳来跳去。中间可能有一些不必要的部分,因此我使用了一个模板

- (void)update
{
    float aspect = fabsf(self.view.bounds.size.width / self.view.bounds.size.height);
    GLKMatrix4 projectionMatrix = GLKMatrix4MakePerspective(GLKMathDegreesToRadians(65.0f), aspect, 0.1f, 100.0f);

    self.effect.transform.projectionMatrix = projectionMatrix;

    GLKMatrix4 baseModelViewMatrix = GLKMatrix4MakeTranslation(0.0f, 0.0f, -4.0f);

    // Compute the model view matrix for the object rendered with ES2
    GLKMatrix4 modelViewMatrix = GLKMatrix4MakeTranslation(0.0f, 0.0f, 0.0f);
    modelViewMatrix = GLKMatrix4Rotate(modelViewMatrix, startPoint.y, 0.0f, 1.0f, 0.0f);

    dx = dy = 0;
    modelViewMatrix = GLKMatrix4Multiply(baseModelViewMatrix, modelViewMatrix);

    _normalMatrix = GLKMatrix3InvertAndTranspose(GLKMatrix4GetMatrix3(modelViewMatrix), NULL);

    _modelViewProjectionMatrix = GLKMatrix4Multiply(projectionMatrix, modelViewMatrix);

    _rotation += self.timeSinceLastUpdate * 0.5f;
}
我的触摸行为:

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    startPoint = [touch locationInView:self.view];
}

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    CGPoint point = [touch locationInView:self.view];
    dx = point.y - startPoint.y;
    dy = point.x - startPoint.x;
    startPoint = point;
}

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{

}

提前感谢。

通过苹果图书馆的以下链接可以解决您的问题
[http://developer.apple.com/library/ios/#samplecode/GLSprite/Introduction/Intro.html#//apple_ref/doc/uid/DTS40007325

感谢您的回复,但遗憾的是,该示例没有任何用户通过触摸方式进行交互。