如何使用Cordova获取图像对象？

使用getPicture时，我们会得到一个相对URL或base64image。但是我想向AmazonS3发送一个图像对象。不管怎样，你想这么做吗

下面是我如何获得Base64图像的

// A button will call this function
//
function capturePhoto() {
    // Take picture using device camera and retrieve image as base64-encoded string
    navigator.camera.getPicture(onPhotoDataSuccess, onFail, {
        destinationType: Camera.DestinationType.DATA_URL, 
        quality: 50
    });
}

[更新]现在我需要获取图像作为对象，将其转换为字节数组，并使用REST（PUT）调用将其上载到Amazon S3。

当然可以

照相机/图像源代码

html

文件传输源代码

js

php

---

同样，您也可以将ByTestStream加载到图像标记

      function(success) { // Assuming you are sending the bytestream from the code

         var img  = document.getElementById('image');
         img.src = 'data:image/png;base64,' + success.bytestream;
       }

谢谢。我将尝试：-）我尝试了这个方法，但我发现需要获取图像对象并将其转换为字节数组，然后作为REST调用（PUT）上传。多亏了你的帮助，我把代码改成了URL，并把图片储存在图库中。现在我需要以某种方式将其转换为对象并调用REST服务。我已经阅读了代码，在获得图像url后，我正在创建一个图像对象并设置src。现在我需要将其转换为字节数组，因为upload-REST调用希望图像位于字节数组中。这就是我现在所处的困境。有关于字节数组转换的想法吗？非常感谢您的帮助。您可以使用base64上传到您的数据库中
function onPhotoDataSuccess(imageURI) {
    // Uncomment to view the base64-encoded image data
    console.log(imageURI);
    // Get image handle
    //
    var cameraImage = document.getElementById('image');
    // Unhide image elements
    //
    cameraImage.style.display = 'block';
    // Show the captured photo
    // The inline CSS rules are used to resize the image
    //
    cameraImage.src = imageURI;
}

function capturePhoto() {
    // Retrieve image file location from specified source
    navigator.camera.getPicture(onPhotoDataSuccess, onFail, {
        quality: 30,
        targetWidth: 600,
        targetHeight: 600,
        destinationType: destinationType.FILE_URI,
        saveToPhotoAlbum: true
    });
}

function upload() {
    var img = document.getElementById('image');
    var imageURI = img.src;
    var options = new FileUploadOptions();
    options.fileKey = "file";
    options.fileName = imageURI.substr(imageURI.lastIndexOf('/') + 1);
    options.mimeType = "image/jpeg";
    var params = new Object();
    options.params = params;
    options.chunkedMode = false;
    var ft = new FileTransfer();
    ft.upload(imageURI, "https://www.example.com/upload.php", win, fail,
        options);
}

function win(r) {
    console.log("Code = " + r.responseCode);
    console.log("Response = " + r.response);
    console.log("Sent = " + r.bytesSent);
}

function fail(error) {
    alert("An error has occurred: Code = " + error.code);
    console.log("upload error source " + error.source);
    console.log("upload error target " + error.target);
}

<?php
move_uploaded_file($_FILES["file"]["tmp_name"], '/path/to/file');

      function(success) { // Assuming you are sending the bytestream from the code

         var img  = document.getElementById('image');
         img.src = 'data:image/png;base64,' + success.bytestream;
       }