C++ btree程序可能由于指针而崩溃
我试图按级别顺序打印b树,但它一直崩溃。我不确定真正的原因是什么,但我认为它崩溃是因为指针。我试着使用我在网上找到的一个函数,它可以遍历每一个级别,将其放入队列并打印,但我遇到了这个问题。如果有人有其他方法,请告诉我C++ btree程序可能由于指针而崩溃,c++,b-tree,C++,B Tree,我试图按级别顺序打印b树,但它一直崩溃。我不确定真正的原因是什么,但我认为它崩溃是因为指针。我试着使用我在网上找到的一个函数,它可以遍历每一个级别,将其放入队列并打印,但我遇到了这个问题。如果有人有其他方法,请告诉我 // C++ program for B-Tree insertion #include<iostream> #include <queue> using namespace std; int ComparisonCount
// C++ program for B-Tree insertion
#include<iostream>
#include <queue>
using namespace std;
int ComparisonCount = 0;
// A BTree node
class BTreeNode
{
int *keys; // An array of keys
int t; // Minimum degree (defines the range for number of keys)
BTreeNode **C; // An array of child pointers
int n; // Current number of keys
bool leaf; // Is true when node is leaf. Otherwise false
public:
BTreeNode(int _t, bool _leaf); // Constructor
// A utility function to insert a new key in the subtree rooted with
// this node. The assumption is, the node must be non-full when this
// function is called
void insertNonFull(int k);
// A utility function to split the child y of this node. i is index of y in
// child array C[]. The Child y must be full when this function is called
void splitChild(int i, BTreeNode *y);
// A function to traverse all nodes in a subtree rooted with this node
void traverse();
// A function to search a key in subtree rooted with this node.
BTreeNode *search(int k); // returns NULL if k is not present.
// Make BTree friend of this so that we can access private members of this
// class in BTree functions
friend class BTree;
};
// A BTree
class BTree
{
BTreeNode *root; // Pointer to root node
int t; // Minimum degree
public:
// Constructor (Initializes tree as empty)
BTree(int _t)
{
root = NULL; t = _t;
}
// function to traverse the tree
void traverse()
{
if (root != NULL) root->traverse();
}
// function to search a key in this tree
BTreeNode* search(int k)
{
return (root == NULL) ? NULL : root->search(k);
}
// The main function that inserts a new key in this B-Tree
void insert(int k);
};
// Constructor for BTreeNode class
BTreeNode::BTreeNode(int t1, bool leaf1)
{
// Copy the given minimum degree and leaf property
t = t1;
leaf = leaf1;
// Allocate memory for maximum number of possible keys
// and child pointers
keys = new int[2 * t - 1];
C = new BTreeNode *[2 * t];
// Initialize the number of keys as 0
n = 0;
}
// Function to traverse all nodes in a subtree rooted with this node
/*void BTreeNode::traverse()
{
// There are n keys and n+1 children, travers through n keys
// and first n children
int i;
for (i = 0; i < n; i++)
{
// If this is not leaf, then before printing key[i],
// traverse the subtree rooted with child C[i].
if (leaf == false)
{
ComparisonCount++;
C[i]->traverse();
}
cout << " " << keys[i];
}
// Print the subtree rooted with last child
if (leaf == false)
{
ComparisonCount++;
C[i]->traverse();
}
}*/
// Function to search key k in subtree rooted with this node
BTreeNode *BTreeNode::search(int k)
{
// Find the first key greater than or equal to k
int i = 0;
while (i < n && k > keys[i])
i++;
// If the found key is equal to k, return this node
if (keys[i] == k)
{
ComparisonCount++;
return this;
}
// If key is not found here and this is a leaf node
if (leaf == true)
{
ComparisonCount++;
return NULL;
}
// Go to the appropriate child
return C[i]->search(k);
}
// The main function that inserts a new key in this B-Tree
void BTree::insert(int k)
{
// If tree is empty
if (root == NULL)
{
ComparisonCount++;
// Allocate memory for root
root = new BTreeNode(t, true);
root->keys[0] = k; // Insert key
root->n = 1; // Update number of keys in root
}
else // If tree is not empty
{
// If root is full, then tree grows in height
if (root->n == 2 * t - 1)
{
ComparisonCount++;
// Allocate memory for new root
BTreeNode *s = new BTreeNode(t, false);
// Make old root as child of new root
s->C[0] = root;
// Split the old root and move 1 key to the new root
s->splitChild(0, root);
// New root has two children now. Decide which of the
// two children is going to have new key
int i = 0;
if (s->keys[0] < k)
{
ComparisonCount++;
i++;
}s->C[i]->insertNonFull(k);
// Change root
root = s;
}
else // If root is not full, call insertNonFull for root
root->insertNonFull(k);
}
}
// A utility function to insert a new key in this node
// The assumption is, the node must be non-full when this
// function is called
void BTreeNode::insertNonFull(int k)
{
// Initialize index as index of rightmost element
int i = n - 1;
// If this is a leaf node
if (leaf == true)
{
ComparisonCount++;
// The following loop does two things
// a) Finds the location of new key to be inserted
// b) Moves all greater keys to one place ahead
while (i >= 0 && keys[i] > k)
{
keys[i + 1] = keys[i];
i--;
}
// Insert the new key at found location
keys[i + 1] = k;
n = n + 1;
}
else // If this node is not leaf
{
// Find the child which is going to have the new key
while (i >= 0 && keys[i] > k)
i--;
// See if the found child is full
if (C[i + 1]->n == 2 * t - 1)
{
ComparisonCount++;
// If the child is full, then split it
splitChild(i + 1, C[i + 1]);
// After split, the middle key of C[i] goes up and
// C[i] is splitted into two. See which of the two
// is going to have the new key
if (keys[i + 1] < k)
i++;
}
C[i + 1]->insertNonFull(k);
}
}
// A utility function to split the child y of this node
// Note that y must be full when this function is called
void BTreeNode::splitChild(int i, BTreeNode *y)
{
// Create a new node which is going to store (t-1) keys
// of y
BTreeNode *z = new BTreeNode(y->t, y->leaf);
z->n = t - 1;
// Copy the last (t-1) keys of y to z
for (int j = 0; j < t - 1; j++)
z->keys[j] = y->keys[j + t];
// Copy the last t children of y to z
if (y->leaf == false)
{
ComparisonCount++;
for (int j = 0; j < t; j++)
z->C[j] = y->C[j + t];
}
// Reduce the number of keys in y
y->n = t - 1;
// Since this node is going to have a new child,
// create space of new child
for (int j = n; j >= i + 1; j--)
C[j + 1] = C[j];
// Link the new child to this node
C[i + 1] = z;
// A key of y will move to this node. Find location of
// new key and move all greater keys one space ahead
for (int j = n - 1; j >= i; j--)
keys[j + 1] = keys[j];
// Copy the middle key of y to this node
keys[i] = y->keys[t - 1];
// Increment count of keys in this node
n = n + 1;
}
void BTreeNode::traverse()
{
std::queue<BTreeNode*> queue;
queue.push(this);
while (!queue.empty())
{
BTreeNode* current = queue.front();
queue.pop();
int i;
for (i = 0; i < n; i++)
{
if (leaf == false)
queue.push(current->C[i]);
cout << " " << current->keys[i] << endl;
}
if (leaf == false)
queue.push(current->C[i]);
}
}
// Driver program to test above functions
int main()
{
BTree t(4); // A B-Tree with minium degree 4
srand(29324);
for (int i = 0; i<200; i++)
{
int p = rand() % 10000;
t.insert(p);
}
cout << "Traversal of the constucted tree is ";
t.traverse();
int k = 6;
(t.search(k) != NULL) ? cout << "\nPresent" : cout << "\nNot Present";
k = 28;
(t.search(k) != NULL) ? cout << "\nPresent" : cout << "\nNot Present";
cout << "There are " << ComparisonCount << " comparison." << endl;
system("pause");
return 0;
}
“B-ToE插入”代码> //C++程序
#包括
#包括
使用名称空间std;
int ComparisonCount=0;
//树节点
B类再入节点
{
int*keys;//一个键数组
int t;//最小度数(定义键数的范围)
BTreeNode**C;//子指针数组
int n;//当前的键数
bool leaf;//当节点为leaf时为true,否则为false
公众:
BTreeNode(int _t,bool _leaf);//构造函数
//一个实用函数,用于在以
//此节点。假设为,当此
//函数被调用
void insertNonFull(int k);
//用于拆分此节点的子y的实用函数。i是中y的索引
//子数组C[]。调用此函数时,子数组y必须已满
void splitChild(int i,b绿色节点*y);
//用于遍历以该节点为根的子树中的所有节点的函数
无效遍历();
//在以该节点为根的子树中搜索键的函数。
BTreeNode*search(int k);//如果k不存在,则返回NULL。
//让BTree成为这个的朋友,这样我们就可以访问它的私有成员
//B树函数中的类
朋友类树;
};
//树
B类树
{
BTreeNode*root;//指向根节点的指针
int t;//最小度
公众:
//构造函数(将树初始化为空)
树(内部)
{
root=NULL;t=\u t;
}
//函数遍历树
无效遍历()
{
如果(root!=NULL)根->遍历();
}
//函数来搜索此树中的键
B重节点*搜索(整数k)
{
返回(root==NULL)?NULL:root->search(k);
}
//在此B树中插入新键的主函数
空白插入(int k);
};
//BTreeNode类的构造函数
BTreeNode::BTreeNode(int t1,bool leaf1)
{
//复制给定的最小度数和叶属性
t=t1;
叶=叶1;
//为可能的最大键数分配内存
//和子指针
密钥=新的整数[2*t-1];
C=新的B节点*[2*t];
//将密钥数初始化为0
n=0;
}
//函数遍历以该节点为根的子树中的所有节点
/*void BTreeNode::traverse()
{
//有n个键和n+1个子键,遍历n个键
//和前n个孩子
int i;
对于(i=0;i while (!queue.empty())
{
BTreeNode* current = queue.front();
queue.pop();
int i;
for (i = 0; i < current->n; i++) //*
{
if (current->leaf == false) //*
queue.push(current->C[i]);
cout << " " << current->keys[i] << endl;
}
if (current->leaf == false) //*
queue.push(current->C[i]);
}