C++ GNU GMP中mpz_类的sizeinbase
在C中，我们有C++ GNU GMP中mpz_类的sizeinbase,c++,gmp,C++,Gmp,在C中，我们有mpz\t，我们可以通过 size_t mpz_sizeinbase (const mpz_t op, int base) 在mpz_课上，我试过 counter.sizeinbase(2); 那没用 error: ‘mpz_class {aka class __gmp_expr<__mpz_struct [1], __mpz_struct [1]>}’ has no member named ‘sizeinbase’ size_t size = (co
mpz\tsize_t mpz_sizeinbase (const mpz_t op, int base)
counter.sizeinbase(2);
error: ‘mpz_class {aka class __gmp_expr<__mpz_struct [1], __mpz_struct [1]>}’ has no member named ‘sizeinbase’
size_t size = (counter.sizeinbase(2) + CHAR_BIT-1) / CHAR_BIT;
错误：“mpz_类{aka类{uuu gmp_expr}”没有名为“sizeinbase”的成员
size\u t size=（counter.sizeinbase（2）+CHAR\u BIT-1）/CHAR\u BIT；
mpz_类是否有类似的函数或解决方法？使用
get_mpz_tmpz_tmpz_class x = ...;
size_t xbits = mpz_sizeinbase(x.get_mpz_t(), 2);
至少这在MPIR中有效，我假设它在GMP中也有效。使用
get\u mpz\u tmpz\u tmpz_class x = ...;
size_t xbits = mpz_sizeinbase(x.get_mpz_t(), 2);