C++ 为什么'；t这将取代'；Xs'；有空格'；s int-mapSizeX=30； int-mapSizeY=10； 字符串映射[10][30]； charplayermovement； 对于（int i=0；i

尝试添加以下内容以查看您的竞技场：

    int mapSizeX = 30;
    int mapSizeY = 10;
    string map[10][30];
    char playerMovement;
    for (int i = 0; i < mapSizeY; i++)
    {
        for (int j = 0; j < mapSizeX; j++)
        {
            map[i][j]= "X";
            cout << map[i][j];
        }
        cout << endl;
    }
    for (int i = 1; i < mapSizeY - 1; i++)
    {
        for (int j = 1; j < mapSizeX - 1; j++)
        {
            map[i][j] = " ";
            cout << map[i][j];
        }
        cout << endl;
    }

---

cout您将输出到
cout
两次。在使用X打印整个竞技场后，删除这两个
cout，然后打印整个竞技场，每侧只短一块空白。因此，您将逐个打印它们。您要做的是在相同的嵌套for循环中打印它们，如下所示：

 ... // Previous code without printing

 for (int i = 0; i < mapSizeY; i++)
    {
        for (int j = 0; j < mapSizeX; j++)
        {
            cout << map[i][j];
        }
        cout << endl;
    }

for（int i=0；icout似乎你不明白
cout
是如何工作的。你可能想再看看课本。在第二个循环中，你可以写
cout
 ... // Previous code without printing

 for (int i = 0; i < mapSizeY; i++)
    {
        for (int j = 0; j < mapSizeX; j++)
        {
            cout << map[i][j];
        }
        cout << endl;
    }

for (int i = 0; i < mapSizeY; i++)
{
        for (int j = 0; j < mapSizeX; j++)
        {
            if (i == 0 || j == 0 || i == mapSizeY - 1 || j == mapSizeX - 1) {
                map[i][j] = "X";
                cout << map[i][j];
            }
            else {
                map[i][j] = " ";
                cout << map[i][j];
            }
        }
        cout << endl;
}

for (int i = 0; i < mapSizeY; i++)
{
        for (int j = 0; j < mapSizeX; j++)
        {
            if (i == 0 || j == 0 || i == mapSizeY - 1 || j == mapSizeX - 1) {
                map[i][j] = "X";
            }
            else {
                map[i][j] = " ";
            }
        }
}

for (int i = 0; i < mapSizeY; i++)
{
        for (int j = 0; j < mapSizeX; j++)
        {
                cout << map[i][j];
        }
        cout << endl;
}