C++ 将非专用模板作为模板参数传递

我能做点像这样的事吗

template<class Key, class Data, class Compare = less<Key>, template<typename T> class Allocator<T> = allocator<T> >
    class mymap {
        typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap; 
        typedef vector<Data,Allocator<Data> > storageVector;
}

---

因此，模板被传递给未指定的类，并在以后实例化。

是的，它被称为模板参数，语法为

template <class Key, class Data, class Compare = less<Key>,
          template <typename T> class Allocator = allocator >
class mymap {
    typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap; 
    typedef vector<Data,Allocator<Data> > storageVector;
}

---

是的，这里有一个最小的可编译示例：

#include <map>
#include <vector>
using namespace std;

template <
    class Key,
    class Data,
    class Compare = less<Key>,
    template <typename T> class Allocator = allocator
>
class mymap
{
public:
    typedef map<Key,Data,Compare,Allocator<pair<const Key, Data> > > storageMap; 
    typedef vector<Data,Allocator<Data> > storageVector;
};

int main()
{
    mymap<int,long>::storageMap m;
    mymap<int,long>::storageVector v;
    return 0;
}

---

codemymap.hpp30:错误：标识符T是未定义的模板代码@mmutz嗯，gcc对这样的声明不满意：@akashi:`s/=allocator/=allocator/my fault，很抱歉，谢谢您的帮助