C++ 我如何制作这个C++；程序使用负数吗？ #包括 #包括 使用名称空间std； int main（） { int value1；//这些保存用户输入的原始数字 int值2； int结果； //这将保存要与使用该算法提供的答案进行比较的答案 cout值1； cout值2； int tempnumber1{value1}；//创建一个用于减半的临时变量，同时保存主数字以供以后使用。 向量减半；//这将打开该算法使用的向量减半 不能

应该改成这样,

while (tempnumber1>0);

应该改成这样,

if (halving [i] %2==1)

要容纳负数

#包括
if (halving [i] %2==1 || halving [i] %2==-1)
//Or
if(halving[i] % 2 != 0); //Thanks @stefaanv

#包括
使用名称空间std；
int main（）
{
int value1；//这些保存用户输入的原始数字
int值2；
int结果；
//这将保存要与使用该算法提供的答案进行比较的答案
cout值1；
cout值2；
int tempnumber1{value1}；//创建一个用于减半的临时变量，同时保存主数字以供以后使用。
向量减半；//这将打开该算法使用的向量减半
我能想到的最优雅的：

#include <iostream>
#include <bits/stdc++.h>

using namespace std;

int main()
{

    int value1; // these holds the original numbers inputted by the users
    int value2;
    int result;
    // this holds the answer to be compared against the answer provided by using the algorithm

    cout << "Please Enter the first number to be multiplied"<< endl;
    cin >> value1;
    cout << "Please Enter the second number to be multiplied"<< endl;
    cin >> value2;
    int tempnumber1 {value1};   //create a temp variable for halving while  keeping main numbers stored for later use.
    vector <int> halving;       // this opens this vector halving which the algorithm uses
    cout << "This is the Halving Step" << endl;
    do
    {
        halving.push_back(tempnumber1);
        cout <<tempnumber1 << endl;
        tempnumber1/=2;
    }
    while ((tempnumber1>0 && value1>0) ||(tempnumber1<0 && value1<0));
    cout << " This is the Doubling stage" <<endl;
    int tempnumber2 {value2};
    for (int i=0;   i<halving.size(); i++)
    {
        cout << tempnumber2 << endl;
        tempnumber2*=2;

    }


    int total{0};
    int doubling = value2;
    for (int i =0; i < halving.size(); i++)
    {
        if (abs(halving [i]) % 2==1)
        {
            cout << doubling << " Is Added to total" << endl;
            total += doubling;

        }
        doubling *= 2;      // this is used to avoid having to use two vectors.
    }
    //total /= 2;
    result = value1*value2; // this provides the check value
    cout << "The result is:" << total;
    cout << "[Check Value:" << result << "]" << endl;
}

cout我想你可以用这个（如果我错了，请纠正我）

tempnumber1>0 | | tempnumber1<0
，或者像我们有时写的那样：
tempnumber1！=0
）
将[i]%2！=0减半
？你错了！
isdigit（int）
检查字符是否为十进制数字。如果
为true，则返回非零；如果
为false，则返回非零。因此，您只执行块中的内容，而用户输入的内容不是十进制数字。这不是程序的目标。
if (halving [i] %2==1 || halving [i] %2==-1)
//Or
if(halving[i] % 2 != 0); //Thanks @stefaanv

#include <iostream>
#include <bits/stdc++.h>

using namespace std;

int main()
{

    int value1; // these holds the original numbers inputted by the users
    int value2;
    int result;
    // this holds the answer to be compared against the answer provided by using the algorithm

    cout << "Please Enter the first number to be multiplied"<< endl;
    cin >> value1;
    cout << "Please Enter the second number to be multiplied"<< endl;
    cin >> value2;
    int tempnumber1 {value1};   //create a temp variable for halving while  keeping main numbers stored for later use.
    vector <int> halving;       // this opens this vector halving which the algorithm uses
    cout << "This is the Halving Step" << endl;
    do
    {
        halving.push_back(tempnumber1);
        cout <<tempnumber1 << endl;
        tempnumber1/=2;
    }
    while ((tempnumber1>0 && value1>0) ||(tempnumber1<0 && value1<0));
    cout << " This is the Doubling stage" <<endl;
    int tempnumber2 {value2};
    for (int i=0;   i<halving.size(); i++)
    {
        cout << tempnumber2 << endl;
        tempnumber2*=2;

    }


    int total{0};
    int doubling = value2;
    for (int i =0; i < halving.size(); i++)
    {
        if (abs(halving [i]) % 2==1)
        {
            cout << doubling << " Is Added to total" << endl;
            total += doubling;

        }
        doubling *= 2;      // this is used to avoid having to use two vectors.
    }
    //total /= 2;
    result = value1*value2; // this provides the check value
    cout << "The result is:" << total;
    cout << "[Check Value:" << result << "]" << endl;
}

cout << "This is the Halving Step" << endl;
  do {
    halving.push_back(tempnumber1);
    cout << tempnumber1 << endl;
    tempnumber1 /= 2;
  } while (tempnumber1 != 0);

  int total{0};
  int doubling = value2;
  int sign{0};
  for (int i = 0; i < halving.size(); i++) {
    if ((sign = halving[i] % 2) != 0) {
      cout << doubling*sign << " Is Added to total" << endl;
      total += doubling*sign;
    }
    doubling *= 2;  // this is used to avoid having to use two vectors.
  }

while (isdigit(tempnumber1)==0);