C++ 了解C+中运算符的范围+； #包括 名称空间Foo { 类Baz{}； std:：ostream和操作员

DRTL

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编译器可以找到用户定义的

operator@Kolyunya很高兴能帮上忙！
#include <iostream>

namespace Foo
{
    class Baz { };   

    std::ostream& operator<< ( std::ostream& ostream , const Baz& baz )
    {
        return ostream << "operator<<\n";
    }
}

int main()
{
    std::cout << Foo::Baz();
}

 std::cout << Foo::Baz();

 operator<<(std::cout, Foo::Baz());

 std::operator<<(std::ostream&, /* all the builtin types and Standard strings and streams */)
 Foo::operator<<(std::ostream&, const& Baz)