C++ 在C+中定义元组常量向量的更简洁的方法+;11
我有一个元组的常量向量,其中每个元组包含一个键、名称、数量和值。这就是我对它的定义-C++ 在C+中定义元组常量向量的更简洁的方法+;11,c++,c++11,vector,tuples,stdtuple,C++,C++11,Vector,Tuples,Stdtuple,我有一个元组的常量向量,其中每个元组包含一个键、名称、数量和值。这就是我对它的定义- // tuple of key, name, quantity, value const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{ std::tuple<unsigned char, std::string, unsigned char, float
// tuple of key, name, quantity, value
const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
std::tuple<unsigned char, std::string, unsigned char, float>(0, "mango", 12, 1.01f),
std::tuple<unsigned char, std::string, unsigned char, float>(4, "apple", 101, 22.02f),
std::tuple<unsigned char, std::string, unsigned char, float>(21, "orange", 179, 39.03f),
};
//键、名称、数量、值的元组
const std::vector myTable{
标准:元组(0,“芒果”,12,1.01f),
标准:元组(4,“苹果”,101,22.02f),
标准:元组(21,“橙色”,179,39.03f),
};
在main函数中,我需要每个元组的索引和要处理的所有值。为了简单起见,我使用以下方式打印它们-
for (int index = 0; index < myTable.size(); index++) {
auto key = std::get<0>(myTable[index]);
auto name = std::get<1>(myTable[index]);
auto quantity = std::get<2>(myTable[index]);
auto value = std::get<3>(myTable[index]);
std::cout << " index: " << index
<< " key:" << (int)key
<< " name:" << name
<< " quantity:" << (int)quantity
<< " value:" << value
<< std::endl;
}
for(int index=0;index std::cout您可以使用{}
:
const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
{0, "mango", 12, 1.01f},
{4, "apple", 101, 22.02f},
{21, "orange", 179, 39.03f},
};
const std::vector myTable{
{0,“芒果”,12,1.01f},
{4,“苹果”,101,22.02f},
{21,“橙色”,179,39.03f},
};
只需将上一个代码块中的()
更改为{}
。如果有一些推导或引用破坏了乐趣,也许添加std::make_tuple
可以帮你摆脱困境。它就像一个符咒。请参见此处了解详细信息。我没有必要想太多!
const std::vector<std::tuple<unsigned char, std::string, unsigned char, float> > myTable{
{0, "mango", 12, 1.01f},
{4, "apple", 101, 22.02f},
{21, "orange", 179, 39.03f},
};