C++ mkl库DCT函数实现问题

C++ mkl库DCT函数实现问题,c++,intel-mkl,intel-ipp,C++,Intel Mkl,Intel Ipp,我试图用mkl.lib DCT函数替换ipp.lib DCT函数。 我使用以下基于Ipp的API进行DCT: ippsDCTFwdInitAlloc_32f ippsDCTFwd_32f ippsDCTFwdFree_32f 基于PFB mkl的DCT示例代码: #include <time.h> #include <stdlib.h> #include "mkl.h" int main(int argc, char* argv[]){ float *dpar

我试图用mkl.lib DCT函数替换ipp.lib DCT函数。 我使用以下基于Ipp的API进行DCT:

ippsDCTFwdInitAlloc_32f
ippsDCTFwd_32f
ippsDCTFwdFree_32f
基于PFB mkl的DCT示例代码:

#include <time.h>
#include <stdlib.h>
#include "mkl.h"
int main(int argc, char* argv[]){

    float *dpar;
    float *out;
    MKL_INT    *ipar;
    MKL_INT tt_type,stat,n_1,nn;
    FILE *fp,*fw,*fonce;
    fp = fopen( "D:\\dump\\fileinput.txt","r" );
    if(fp == NULL){
        cout<<"file not created properly"<<endl;
    }
    DFTI_DESCRIPTOR_HANDLE handle = 0;
    int n = 150; /*Hardcoded to run for my code TODO: going to change after integrating into my main codebase.As I can't attach my full fileinput.txt .So just taken n value = 150 */
    nn = (MKL_INT)n;
    tt_type = MKL_STAGGERED_COSINE_TRANSFORM;

    n_1 = nn + 1 ;
    out = (float*)malloc((n+1)*sizeof(float));
    dpar= (float*)malloc((5*n_1/2+2)*sizeof(float));
    ipar= (MKL_INT*)malloc((128)*sizeof(int));
    s_init_trig_transform(&n_1,&tt_type,ipar,dpar,&stat);
    for (int srcSize =0 ;srcSize< n ; srcSize++)
    {
        fscanf(fp,"%f\n",&out[srcSize]);
    }
    fclose(fp);
    if (stat != 0)
    {
        printf("\n============================================================================\n");
        printf("FFTW2MKL FATAL ERROR: MKL TT initialization has failed with status=%d\n",(MKL_INT)stat);
        printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
        printf("to find what went wrong...\n");
        printf("============================================================================\n");
        return NULL;
    }
    ipar[10] = 1;    //nx, that is, the number of intervals along the x-axis, in the Cartesian case.
    ipar[14] = n_1;  //specifies the internal partitioning of the dpar array.
    ipar[15] = 1;    //value of ipar[14]+1,Specifies the internal partitioning of the dpar array.
    s_commit_trig_transform(out,&handle,ipar,dpar,&stat);
    if (stat != 0)
    {
        printf("\n============================================================================\n");
        printf("FFTW2MKL FATAL ERROR: MKL TT commit step has failed with status=%d\n",(MKL_INT)stat);
        printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
        printf("to find what went wrong...\n");
        printf("============================================================================\n");
        return NULL;
    }
    s_forward_trig_transform(out,&handle,ipar,dpar,&stat);
    if (stat != 0)
    {
        printf("\n============================================================================\n");
        printf("FFTW2MKL FATAL ERROR: MKL TT commit step has failed with status=%d\n",(MKL_INT)stat);
        printf("Please refer to the Trigonometric Transform Routines Section of MKL Manual\n");
        printf("to find what went wrong...\n");
        printf("============================================================================\n");
        return NULL;
    }
    free_trig_transform(&handle,ipar,&stat);
    printf("\n===== DCT GOT OVER ======== \n");

    return 0;

}

我想你说的是这些函数的dpar参数。 实际上,它们不用于计算结果。它们仅用于存储TT计算中使用的中间sin/cos数据

对于计算功能: d_前向触发变换(双f[],DFTI描述符_句柄*句柄,MKL _INTIPAR[],双dpar[],MKL _INT*stat)

输入和输出都是相同大小的F[]。 有关更多信息,请参阅以下链接:

我将对此进行检查。但至少要按原样运行代码,您应该使用“cout”或“printf”。或者添加#使用名称空间std包含“iostream”;它帮助我理解了一些要点。但它仍然不能解决问题!!
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