C++ C\C中的简单翻转缓冲区（垂直）问题++

我试图翻转缓冲区，但缓冲区未得到完全处理。 是一个像素缓冲区，我基本上需要垂直翻转它。 谁能看出我做错了什么？提前谢谢

void flipVertically(unsigned int* buffer, const unsigned int width, const unsigned int height)
{
    const unsigned int rowWidth = width; // Length of a row
    const unsigned int rows = height / 2; // Iterate only half the buffer to get a full flip
    unsigned int* tempRow = (unsigned int*)malloc(rowWidth);

    for (int rowIndex = 0; rowIndex < rows; rowIndex++)
    {
        memcpy(tempRow, buffer + (rowIndex * rowWidth), rowWidth);
        memcpy(buffer + (rowIndex * rowWidth), buffer + (height - rowIndex - 1) * rowWidth, rowWidth);
        memcpy(buffer + (height - rowIndex - 1) * rowWidth, tempRow, rowWidth);
    }

    free(tempRow);
}

这样行吗

void flip(unsigned* buffer, unsigned width, unsigned height)
{
    unsigned rows = height / 2; // Iterate only half the buffer to get a full flip
    unsigned* tempRow = (unsigned*)malloc(width * sizeof(unsigned));

    for (unsigned rowIndex = 0; rowIndex < rows; rowIndex++)
    {
        memcpy(tempRow, buffer + rowIndex * width, width * sizeof(unsigned));
        memcpy(buffer + rowIndex * width, buffer + (height - rowIndex - 1) * width, width * sizeof(unsigned));
        memcpy(buffer + (height - rowIndex - 1) * width, tempRow, width * sizeof(unsigned));
    }

    free(tempRow);
}

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你能澄清一下你所说的翻转是什么意思吗？你是说反向吗？你是说转置吗？这是C还是C++？如果是C++，为什么使用指针？什么是缓冲像素？到底是什么出错了？注意：你把行宽传递给MeMcPy，而你可能想要RoWix**sieOff**。@ AlexChamberlain，我想它是一个2D数组，按顺序存储在内存中，需要垂直翻转行[0 ]行[W-1 ]，行[1 ]行[W2]等。