C++ 编译多个c+时架构x86_64的未定义符号+；文件夹

lineTypeUse.cpp

#include <iostream>
#include "lineType.h"

using namespace std;


int main()
{
    Line L1(3, 3, 5);
    cout << "Line 1:"<<endl;
    L1.NonVertical();


    cout << "Line 2:"<<endl;
    Line L2(2, 1, 5);
    L2.NonVertical();

    if (L1.isParallel (L2, L1.slope()))
        cout<< "Two lines are parallel"<< endl;
    else 
        cout<<"Not parallel"<<endl;

    L1.isPerpendicular(L2, L1.slope());

    if (!L1.isParallel(L2, L1.slope()))
        L1.doubleersection(L2);

        system("pause");
}

lineTypeImp.cpp

#include <iostream>
#include "lineType.h"
using namespace std;

Line::Line(double x, double y, double z)
{
        a=x;
        b=y;
        c=z;    
}

double Line::getA()
{
    return a;
}

double Line::getB()
{
    return b;
}

double Line::getC()
{
    return c;
}

double Line::slope()
{
    return -a/b;
}


void Line::NonVertical()
{
    if (b!=0)
        cout<<"Slope is:"<< slope()<<endl;
    else
        cout<<"Vertical"<<endl;
}


bool Line::isEqual(Line L2)
{
    if ( (a==L2.getA()&& b==L2.getB() && 
            c==L2.getC()) 
        || (a/L2.getA()==b/L2.getB()==c/L2.getC()))
        return true;
    else
        return false;
}

bool Line::isParallel(Line& L2, double s1) const
{
    if ((s1==L2.slope())
        || (b==0 && L2.getA()==0))
        return true;
    else
        return false;
}

void Line::isPerpendicular(Line& L2, double s1) const
{
    if (((a==0 && L2.getB()==0)
            || (L2.getA()==0 && b==0))
            || (L2.slope()* s1==-1))
        cout<<"Two lines are Perpendicular"<<endl;      
}

void Line::doubleersection(Line& L2) const 
{
    double x,y;
    x=((b*L2.getC()) - (L2.getB()*c)) /
                        ((a*L2.getB()) - (L2.getA()*b));
    y=((L2.getA()*c)-(a*L2.getC())) /
                        ((a*L2.getB())-(L2.getA()*b));
    cout<<"doubleersection podouble:  ("<<x<<",  "<<y<<")"<<endl;
}

下面是我使用的cmpilling命令

g++-o lineTypeImp.cpp lineTypeUse.cpp

---

如果有人能帮助

在

-o

之后插入输出文件名或将其完全删除，我将不胜感激。并最终检查

lineTypeImp.cpp

的内容：它可能已被覆盖。谢谢你g++lineTypeImp.cpp lineTypeUse.cpp-o lineType解决了它：）

#include <iostream>
#include "lineType.h"
using namespace std;

Line::Line(double x, double y, double z)
{
        a=x;
        b=y;
        c=z;    
}

double Line::getA()
{
    return a;
}

double Line::getB()
{
    return b;
}

double Line::getC()
{
    return c;
}

double Line::slope()
{
    return -a/b;
}


void Line::NonVertical()
{
    if (b!=0)
        cout<<"Slope is:"<< slope()<<endl;
    else
        cout<<"Vertical"<<endl;
}


bool Line::isEqual(Line L2)
{
    if ( (a==L2.getA()&& b==L2.getB() && 
            c==L2.getC()) 
        || (a/L2.getA()==b/L2.getB()==c/L2.getC()))
        return true;
    else
        return false;
}

bool Line::isParallel(Line& L2, double s1) const
{
    if ((s1==L2.slope())
        || (b==0 && L2.getA()==0))
        return true;
    else
        return false;
}

void Line::isPerpendicular(Line& L2, double s1) const
{
    if (((a==0 && L2.getB()==0)
            || (L2.getA()==0 && b==0))
            || (L2.slope()* s1==-1))
        cout<<"Two lines are Perpendicular"<<endl;      
}

void Line::doubleersection(Line& L2) const 
{
    double x,y;
    x=((b*L2.getC()) - (L2.getB()*c)) /
                        ((a*L2.getB()) - (L2.getA()*b));
    y=((L2.getA()*c)-(a*L2.getC())) /
                        ((a*L2.getB())-(L2.getA()*b));
    cout<<"doubleersection podouble:  ("<<x<<",  "<<y<<")"<<endl;
}

Undefined symbols for architecture x86_64:
  "Line::NonVertical()", referenced from:
      _main in lineTypeUse-c3101c.o
  "Line::slope()", referenced from:
      _main in lineTypeUse-c3101c.o
  "Line::Line(double, double, double)", referenced from:
      _main in lineTypeUse-c3101c.o
  "Line::isParallel(Line&, double) const", referenced from:
      _main in lineTypeUse-c3101c.o
  "Line::doubleersection(Line&) const", referenced from:
      _main in lineTypeUse-c3101c.o
  "Line::isPerpendicular(Line&, double) const", referenced from:
      _main in lineTypeUse-c3101c.o
ld: symbol(s) not found for architecture x86_64
clang: error: linker command failed with exit code 1 (use -v to see invocation)