C++ OpenCV马氏函数用于计算两幅图像之间的距离

我正在使用OpenCV测试从同一环境中拍摄的两幅图像之间的相似性

我有一系列相同移动环境的照片。因此，作为A和B这两个二值图像的边缘的两个连续图像的环境，我做如下：

Mat mean;
mean.create(a.rows, a.cols, a.type());

mean += a;
mean += b;
mean/=2;

Mat covar, mean;

calcCovarMatrix(mean, covar, mean, COVAR_NORMAL | COVAR_ROWS, CV_8UC1);

Mat icovar = covar.inv();

std::cout<<"type a:"<<a.type()<<"\n";
std::cout<<"type b:"<<b.type()<<"\n";
std::cout<<"icovar type:"<<icovar.type()<<"\n";
std::cout<<"a cols:"<<a.cols<<"\n";
std::cout<<"a rows:"<<a.rows<<"\n";
std::cout<<"b cols:"<<b.cols<<"\n";
std::cout<<"b rows:"<<b.rows<<"\n";
std::cout<<"icovar cols:"<<icovar.cols<<"\n";
std::cout<<"icovar rows:"<<icovar.rows<<"\n";

double mahalDistance = Mahalanobis(a, b, icovar);

马氏距离函数抛出如下错误：

Mat mean;
mean.create(a.rows, a.cols, a.type());

mean += a;
mean += b;
mean/=2;

Mat covar, mean;

calcCovarMatrix(mean, covar, mean, COVAR_NORMAL | COVAR_ROWS, CV_8UC1);

Mat icovar = covar.inv();

std::cout<<"type a:"<<a.type()<<"\n";
std::cout<<"type b:"<<b.type()<<"\n";
std::cout<<"icovar type:"<<icovar.type()<<"\n";
std::cout<<"a cols:"<<a.cols<<"\n";
std::cout<<"a rows:"<<a.rows<<"\n";
std::cout<<"b cols:"<<b.cols<<"\n";
std::cout<<"b rows:"<<b.rows<<"\n";
std::cout<<"icovar cols:"<<icovar.cols<<"\n";
std::cout<<"icovar rows:"<<icovar.rows<<"\n";

double mahalDistance = Mahalanobis(a, b, icovar);

OpenCV错误：Mahalanobis中的断言失败type==v2.type&&type==icovar.type&&sz==v2.size&&len==icovar.rows&&len==icovar.cols，file/Users/felipefujioka/Documents/Developer/tg/OpenCV-3.0.0-beta/modules/core/src/matmul.cpp，第2486行 libc++abi.dylib:cv:：exception:/Users/felipefujioka/Documents/Developer/tg/opencv-3.0.0-beta/modules/core/src/matmul.cpp:2486:error:-215 type==v2.type&&type==icovar.type&&sz==v2.size&len==icovar.rows&&len==icovar.cols函数中的icovar.cols

我很想知道我错在哪里。提前感谢。

您在代码中混合了a和ma，b和mb。您是否尝试过马哈拉诺比斯玛、mb、icovar？

符合文档：

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A和B必须是1D数组而不是矩阵

对不起，只有A和B，只是一个输入错误，大小和马氏体是用相同的矩阵计算的