C++ c++；结构中的快速查找

我有个小问题。我必须写一个函数，我不知道怎么写。 我什么都试过了

#include <iostream>
#include <stdlib.h>
#include <string>
#include <list>
#include <algorithm>

using namespace std;

struct sBase
{
    string NAME;
    string AGE;

};

list <sBase> FIND_NAME(list <sBase> &MYLIST_ONE, const string Name, bool PART)
{
    list <sBase> NEW;
    list <sBase>::iterator SOLUTION = find(MYLIST_ONE.begin(), MYLIST_ONE.end(), Name); // FULL OF ERRORS . I NEED HELP HERE
    NEW.push_back(*SOLUION);

    return NEW;
}

int main()
{
    list <sBase> MYLIST_ONE;//List including people. I used another function that add people to this.

    string Name
    cout << "Type a name : ";
    getline(cin, Name);

    string ASK;
    bool PART;
    string yes = "YES", no = "NO";

    cout << "Is name only a part of a text ?(YES OR NO) :";
    getline(cin, ASK);

    if (ASK = yes)
        PART = true;
    if (ASK = no)
        PART = false;

    list <sBase> MYLIST_ONE = FIND_NAME(list <sBase> &MYLIST, const string Name, bool PART) //FUCTON SHOULD RETURN A NEW LIST INCLUDING ONLY STRUCTURE OF THIS ONE PEARSON


    system("pause");
    return 0;
}

---

如果您能帮助我，我将不胜感激。

稍微重构一下，删除（大部分）大写的变量名，留下以下内容：

struct sBase
{
    string name;
    string age;

};

struct has_name_like
{
    has_name_like(const std::string& name)
    : _name(name)
    {}

    bool operator()(const sBase& sbase) const
    {
        return (sbase.name == _name);
    }

private:
    std::string _name;
};

list <sBase> find_name(const list <sBase>& input_list, const string Name, bool PART)
{
    list <sBase> result;
    list <sBase>::const_iterator iter = find_if(input_list.begin(),
                                                input_list.end(),
                                                has_name_like(Name));
    if(iter != input_list.end()) {
        result.push_back(*iter);
    }
    return result;
}

int main()
{
    list <sBase> mylist_one;//List including people. I used another function that add people to this.

    string Name;
    cout << "Type a name : ";
    getline(cin, Name);

    string ASK;
    bool PART = false;
    static const string yes = "YES", no = "NO";

    cout << "Is name only a part of a text ?(YES OR NO) :";
    getline(cin, ASK);

    if (ASK == yes)
        PART = true;
    if (ASK == no)
        PART = false;

    list <sBase> mylist_two = find_name(mylist_one, Name, PART);


    system("pause");
    return 0;
}

structsbase
{
字符串名；
弦年龄；
};
结构具有类似的名称
{
具有类似的名称（const std:：string和name）
：_姓名（姓名）
{}
布尔运算符（）（常量sBase和sBase）常量
{
返回（sbase.name==\u name）；
}
私人：
std:：string _name；
};
列表查找名称（常量列表和输入列表、常量字符串名称、布尔部分）
{
列出结果；
list:：const_iterator iter=find_if（input_list.begin（），
input_list.end（），
有像（名字）一样的名字；
if（iter！=input_list.end（））{
结果：推回（*iter）；
}
返回结果；
}
int main（）
{
list mylist_one；//包括人的列表。我使用了另一个函数将人添加到此列表中。
字符串名；
库特
struct sBase
{
    string name;
    string age;

};

struct has_name_like
{
    has_name_like(const std::string& name)
    : _name(name)
    {}

    bool operator()(const sBase& sbase) const
    {
        return (sbase.name == _name);
    }

private:
    std::string _name;
};

list <sBase> find_name(const list <sBase>& input_list, const string Name, bool PART)
{
    list <sBase> result;
    list <sBase>::const_iterator iter = find_if(input_list.begin(),
                                                input_list.end(),
                                                has_name_like(Name));
    if(iter != input_list.end()) {
        result.push_back(*iter);
    }
    return result;
}

int main()
{
    list <sBase> mylist_one;//List including people. I used another function that add people to this.

    string Name;
    cout << "Type a name : ";
    getline(cin, Name);

    string ASK;
    bool PART = false;
    static const string yes = "YES", no = "NO";

    cout << "Is name only a part of a text ?(YES OR NO) :";
    getline(cin, ASK);

    if (ASK == yes)
        PART = true;
    if (ASK == no)
        PART = false;

    list <sBase> mylist_two = find_name(mylist_one, Name, PART);


    system("pause");
    return 0;
}