C++中的64次时间计算 FILETIME ftTime; GetSystemTimeAsFileTime(&ftTime); struct DateTime { unsigned int dwLowDateTime; unsigned int dwHighDateTime; }; DateTime myTime; myTime.dwHighDateTime = (unsigned int)ftTime.dwHighDateTime; myTime.dwLowDateTime = (unsigned int)ftTime.dwLowDateTime; ussigned __int64 AsUInt64_t unsigned __int64 myInt64Time = *(unsigned __int64*)&myTime; // I have Getstring format from date time some thing like this below Format() { SYSTEMTIME systemTime; FileTimeToSystemTime(&fileTime, &systemTime); const char* formatString = "%04d-%02d-%02d %02d:%02d:%02d.%03d"; // I have few variable declartions to be used for snprintf which is not mentioned here. apiResult = _snprintf_s(pBuffer, sizeOfBuffer, count, formatString, systemTime.wYear, systemTime.wMonth, systemTime.wDay, systemTime.wHour, systemTime.wMinute, systemTime.wSecond, systemTime.wMilliseconds); } DateTime startTime = now(); // some how I am getting latest time here. sleep(5s); // sleeping for 5 seconds. DateTime endTime = now(); // i.e., after 5 seconds. std::cout << "\nOn Start Time:" << startTime.Format() << std::endl; std::cout << "On End Tme: " << endTime.Format() << std::endl; std::cout << "On Start Read " << *(unsigned __int64*)&startTime << std::endl; std::cout << "On End Read " << *(unsigned __int64*)&endtime<< std::endl; ///////////////////

我的问题是，我想根据给定的间隔，将边界划分为相等的间隔，例如每间隔2秒。我该怎么做

上限范围/间隔

例如，开始时间：12:00:00:0000，结束时间为12:01:52:00099。间隔是16秒，然后我们有7个间隔

unsigned __int64 interval =16;

如果我在上面使用int逻辑，如果我使用*unsigned\uu int64*&endtime-*unsigned\uu int64*&startTime/interval，我不会得到7？如何修复它？

FILETIME结构包含一个64位值，表示自1601年1月1日UTC以来的100纳秒间隔数

检查此链接：

因此，对两个FILETIME变量进行减法运算可以得到以纳秒为单位的时间差

除以16秒不会得到你想要的

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除以16*10^9或使用difftime API为您执行此计算并以秒为单位返回时间差

您是否已经考虑过difftime API。这使得时间及其差异的实现更加容易。好的，starttime和endtime是文件时间，是100纳秒的倍数。看起来你假设它们是秒？

unsigned __int64 interval =16;