C++ 如何在c++；？

为动态对象数组设置一个值被证明是很棘手的。我正试图用一种经典的方法来做这件事

void Function(CallsOfTheObject * r){
  const char DELIM = '>' ;
  ifstream file("file.txt"); 
  string sTemp; 
  int ri = 1;

  while(getline(file, sTemp)) {
    if(!sTemp.empty() && sTemp[0]==DELIM){
        Expand(r, ri);
        r[ri].setName(sTemp.substr(1)); //The line resulting with error

以及其他使用的功能和方法：

void Expand(CallsOfTheObject *r, int ri){
  CallsOfTheObject* newR = new CallsOfTheObject[ri];
  for (int i = 0; i < ri; i++){
      if(r[i].getName() != ""){
         newR[i] = r[i];
      }else{
          newR[i] = CallsOfTheObject();
      }
  }
  delete []r;
  r = newR;
}

我不断地发现这个错误：

System.Runtime.InteropServices.SEHException was unhandled
Message: External component has thrown an exception.

我的猜测是，我没有在某处释放内存，或者犯了一个很小的错误，比如打字错误

编辑：我向扩展函数添加了指针符号，但唯一更改的是错误：

System.AccessViolationException was unhandled
Message: Attempted to read or write protected memory. This is often an indication that other memory is corrupt.

看起来我没有清除一些内存，或者试图以不合适的方式覆盖现有的内存。至少我发布的代码看起来很干净。。。对我来说

编辑2：我正在查看我的调用堆栈，但它没有告诉我多少。你能告诉我那是什么意思吗

    S2_L2.exe!std::char_traits<char>::copy(char* _First1, char* _First2, unsigned int _Count) Line 497  C++
    S2_L2.exe!std::basic_string<char,std::char_traits<char>,std::allocator<char> >::assign(std::basic_string<char,std::char_traits<char>,std::allocator<char> >& _Right, unsigned int _Roff, unsigned int _Count) Line 904 + 0x28 bytes C++
    S2_L2.exe!std::basic_string<char,std::char_traits<char>,std::allocator<char> >::assign(std::basic_string<char,std::char_traits<char>,std::allocator<char> >& _Right) Line 888 + 0x13 bytes  C++
    S2_L2.exe!std::basic_string<char,std::char_traits<char>,std::allocator<char> >::operator=(std::basic_string<char,std::char_traits<char>,std::allocator<char> >& _Right) Line 764 + 0xc bytes    C++
    S2_L2.exe!Recipe::setName(std::basic_string<char,std::char_traits<char>,std::allocator<char> >* a) Line 22 + 0xb bytes  C++
    S2_L2.exe!InputR(Recipe&& r) Line 146   C++
>   S2_L2.exe!main(array<System::String^> ^ args) Line 120  C++

S2_L2.exe！STD：：CARY: 497：C++（CAR**FILST1，CHAR**FiSTST2，无符号int Syt）
S2_L2.exe！STD::Basic SqrS:：赋值（STD:Stase:Basic Syth＆YeLoad，未签名int yRoFF，未签名int xCalt）904 +0x28字节C++
S2_L2.exe！STD::Basic字符串：：赋值（STD:：Basic字符串和右）行888 +0x13字节C++
S2_L2.exe！STD:：Basic SqcSn::操作符=（STD::Basic字符串和右）行764 +0xC字节C++
S2_L2.exe！秘诀：：StNeNT（STD::Basic字符串S*A）行22 +0xB字节C++
S2_L2.exe！InputR（配方＆）146线C++
>S2_L2.exe！主（数组^ ARGS）120行C++

Expand

按值接收指针

r

，然后继续更改它。除非通过引用传递指针（

CallsOfTheObject*&r

），否则调用者无法看到这些更改。另外，如果

CallsOfTheObject

似乎是一个动态数组，请改用

std:vector

。这既简单又安全。在调用扩展之前，“r”在哪里分配？我希望我可以使用向量！不幸的是，我必须生成一个可行的动态数组样本……在我看来，在将其发送到扩展之前，您并没有初始化r。为什么不能使用向量？我确实初始化了它的主函数（在其中调用函数（CallsOfTheObject*r=newcallsoftheobject[0]；）的函数）。我至少不能使用动态数组一次，因为这是一项家庭作业，旨在检查我们对动态数组的理解程度。

    S2_L2.exe!std::char_traits<char>::copy(char* _First1, char* _First2, unsigned int _Count) Line 497  C++
    S2_L2.exe!std::basic_string<char,std::char_traits<char>,std::allocator<char> >::assign(std::basic_string<char,std::char_traits<char>,std::allocator<char> >& _Right, unsigned int _Roff, unsigned int _Count) Line 904 + 0x28 bytes C++
    S2_L2.exe!std::basic_string<char,std::char_traits<char>,std::allocator<char> >::assign(std::basic_string<char,std::char_traits<char>,std::allocator<char> >& _Right) Line 888 + 0x13 bytes  C++
    S2_L2.exe!std::basic_string<char,std::char_traits<char>,std::allocator<char> >::operator=(std::basic_string<char,std::char_traits<char>,std::allocator<char> >& _Right) Line 764 + 0xc bytes    C++
    S2_L2.exe!Recipe::setName(std::basic_string<char,std::char_traits<char>,std::allocator<char> >* a) Line 22 + 0xb bytes  C++
    S2_L2.exe!InputR(Recipe&& r) Line 146   C++
>   S2_L2.exe!main(array<System::String^> ^ args) Line 120  C++