C++ 在两个不同的线程(解决方案中没有线程)中使用SDL2渲染显示两个或多个不同的动画。C++;
我试图显示两个不同的动画,两个功能,一个渲染和两个线程 每次运行代码时,我都会遇到不同类型的错误。 例如:刷新函数中的分段默认值(行SDL_RenderPresent(w1.renderer);)以及其他奇怪的错误。每次都不一样 我知道如何在两个不同的线程中使用渲染。但是我不知道如何解决这个问题 当我只运行其中一个线程时,一切正常。但他们两个都不行 我只想在窗口周围显示不同的图形。(始终使用sdl2) 这是我的密码: 窗口h:C++ 在两个不同的线程(解决方案中没有线程)中使用SDL2渲染显示两个或多个不同的动画。C++;,c++,linux,multithreading,animation,C++,Linux,Multithreading,Animation,我试图显示两个不同的动画,两个功能,一个渲染和两个线程 每次运行代码时,我都会遇到不同类型的错误。 例如:刷新函数中的分段默认值(行SDL_RenderPresent(w1.renderer);)以及其他奇怪的错误。每次都不一样 我知道如何在两个不同的线程中使用渲染。但是我不知道如何解决这个问题 当我只运行其中一个线程时,一切正常。但他们两个都不行 我只想在窗口周围显示不同的图形。(始终使用sdl2) 这是我的密码: 窗口h: class Window { public: SDL_Window
class Window
{
public:
SDL_Window *window1;
int background,windowWidth,windowHeight,windowXcoord,windowYcoord;
SDL_Renderer * renderer;
SDL_Renderer * renderer2;
Window();
};
void refresh();
extern Window w1;
window.cpp:
Window w1;
Window::Window()
{
window1=nullptr;
background = 0xffffff;
windowWidth=700; windowHeight=500;
windowXcoord = 650; windowYcoord = 0;
this->window1 =
SDL_CreateWindow("Window",windowXcoord,windowYcoord,
windowWidth,windowHeight, SDL_WINDOW_SHOWN);
this->renderer = SDL_CreateRenderer( this->window1, -1 ,
SDL_RENDERER_ACCELERATED);
SDL_SetRenderDrawColor( this->renderer, 255, 255, 255, 255 );
SDL_RenderClear( this->renderer );
SDL_RenderPresent(this->renderer);
}
// this function is called everytime an object or function want to "refresh" the window.
void refresh(){
// clearing the window
SDL_SetRenderDrawColor( w1.renderer, 255, 255, 255,0 );
SDL_RenderClear( w1.renderer );
// r1, the first Rects object to animate.
SDL_SetRenderDrawColor( w1.renderer,255,0,0,255);
SDL_RenderFillRect( w1.renderer, &r1.rect );
// r2, the second Rects.
SDL_SetRenderDrawColor( w1.renderer,255,0,255,255);
SDL_RenderFillRect( w1.renderer, &r2.rect );
SDL_RenderPresent(w1.renderer);
}
矩形h:
class Rects
{
public:
SDL_Rect rect;
Rects();
};
extern Rects r1, r2;
void moveR1();
void moveR2();
rects.cpp:
Rects::Rects()
{ }
Rects r1,r2;
// moveR1 and moveR2, (just some dumm animations-example)
void moveR1(){
r1.rect.x=400; r1.rect.y=100;
r1.rect.w =40; r1.rect.h =10;
SDL_SetRenderDrawColor( w1.renderer,255,0,0,255);
SDL_RenderFillRect( w1.renderer, &r1.rect );
{
for (int u = 1; u<=5;u++){
r1.rect.x=200; r1.rect.y=100;
r1.rect.w =50; r1.rect.h =50;
refresh();
for (int i = 1; i <=200; i++){
r1.rect.x-=1;
usleep (7000);
refresh();
}
}
}
}
void moveR2(){
r2.rect.x=200; r2.rect.y=100;
r2.rect.w =40; r2.rect.h =10;
SDL_SetRenderDrawColor( w1.renderer,255,255,0,255);
SDL_RenderFillRect( w1.renderer, &r2.rect );
{
for (int u = 1; u<=5;u++){
check
r2.rect.x=200; r2.rect.y=100;
r2.rect.w =50; r2.rect.h =50;
refresh();
for (int i = 1; i <=200; i++){
r2.rect.x+=1; r2.rect.y+=1;
usleep (7000);
refresh();
}
}
}
}
欢迎任何有礼貌的帮助,我在这里学习
当我只运行其中一个线程时,一切正常。但他们两个都不行
根据2D加速渲染(也称为SDL_render.h
)的定义,换句话说,是SDL_RenderPresent
所在的位置:
此API不是为从多个线程使用而设计的,有关详细信息,请参阅
你不可能很快做到这一点。通过查看错误的描述,它看起来像一个UB,指向错误的链接可能会为您提供所有详细信息
我只想在窗口周围显示不同的图形
您无需使用两个线程即可完成此操作。您可以只更新位置、动画和图形所需的任何内容,并从同一线程显示它们。没有什么可以阻止您在调用
SDL\u RenderPresent
之前多次调用同一函数(例如SDL\u RenderCopy
)
如果每个图形需要一个线程,那么视频上有数千个多边形的游戏呢?//多亏了skypjack,我才能够解决这个问题
// thanks to skypjack, i am able to solve the problem
// HOW TO PRESENT TWO (OR MORE) GRAPHICS WITH SDL_RENDERER WITHOUT USING THREADS.
// The two rectangle animation are just and example.
// It could be whatever we want to show.
// In this case, just two rectangles moving around.
#include <unistd.h>
#include <SDL.h>
using namespace std;
SDL_Window *window1;
int background, windowWidth, windowHeight,windowXcoord,
windowYcoord;
SDL_Rect rectangle1;
SDL_Rect rectangle2;
SDL_Renderer *renderer;
int sequence1;
int sequence2;
void moveRectangle1(), moveRectangle2();
int main()
{
window1=nullptr;
background = 0xffffff;
windowWidth=700; windowHeight=500;
windowXcoord = 650; windowYcoord = 0;
window1 = SDL_CreateWindow("Main
Window",windowXcoord,windowYcoord, windowWidth,windowHeight,
SDL_WINDOW_SHOWN);
renderer = SDL_CreateRenderer( window1, -1 ,
SDL_RENDERER_ACCELERATED);
SDL_SetRenderDrawColor( renderer, 255, 255, 255, 255 );
SDL_RenderClear( renderer );
SDL_RenderPresent(renderer);
rectangle1.x = 100; rectangle1.y = 100; rectangle1.h = 40;
rectangle1.w = 40;
rectangle2.x = 100; rectangle2.y = 100; rectangle2.h = 40;
rectangle2.w = 40;
for (int i = 1;i<500;i++){
SDL_SetRenderDrawColor( renderer, 255, 255, 255,0 );
SDL_RenderClear( renderer );
// chequear return (cerrar programa)
moveRectangle1();
moveRectangle2();
SDL_RenderPresent(renderer);
usleep (12000);
}
return 0;
}
void moveRectangle1(){
sequence1++;
if (sequence1 <= 50){ rectangle1.x++; }
else if (sequence1 <= 100){ rectangle1.x--; }
else { sequence1 = 0; }
SDL_SetRenderDrawColor(renderer,255,0,0,255);
SDL_RenderFillRect(renderer, &rectangle1 );
}
void moveRectangle2(){
sequence2++;
if (sequence2 <= 100){ rectangle2.y++; }
else if (sequence2 <= 200){ rectangle2.y--; }
else { sequence2 = 0; }
SDL_SetRenderDrawColor(renderer,0,200,0,255);
SDL_RenderFillRect( renderer, &rectangle2 );
}
//如何在不使用线程的情况下使用SDL_渲染器呈现两个(或更多)图形。
//这两个矩形动画只是示例。
//它可以是我们想展示的任何东西。
//在这种情况下,只有两个矩形在移动。
#包括
#包括
使用名称空间std;
SDL_窗口*窗口1;
int背景、窗宽、窗高、windowXcoord、,
窗口坐标;
SDL矩形1;
SDL矩形2;
SDL_渲染器*渲染器;
int序列1;
int序列2;
void moveRectangle1(),moveRectangle2();
int main()
{
window1=nullptr;
背景=0xffffff;
窗宽=700;窗高=500;
windowXcoord=650;windowYcoord=0;
window1=SDL_CreateWindow(“主
窗口”,窗口中心,窗口中心,窗口中心,窗口宽度,窗口高度,
SDL_窗口(如图所示);
renderer=SDL_CreateRenderer(窗口1,-1,
SDL_(加速);
SDL_SetRenderDrawColor(渲染器,255、255、255);
SDL_渲染器(渲染器);
SDL_渲染器呈现(渲染器);
矩形1.x=100;矩形1.y=100;矩形1.h=40;
矩形1.w=40;
矩形2.x=100;矩形2.y=100;矩形2.h=40;
矩形2.w=40;
对于(int i=1;我是对的!我明白了,我将尝试不使用线程。谢谢你skypjack。skypjack,我发布了一个答案,其中的解决方案灵感来源于你教我的内容。再次感谢。
// thanks to skypjack, i am able to solve the problem
// HOW TO PRESENT TWO (OR MORE) GRAPHICS WITH SDL_RENDERER WITHOUT USING THREADS.
// The two rectangle animation are just and example.
// It could be whatever we want to show.
// In this case, just two rectangles moving around.
#include <unistd.h>
#include <SDL.h>
using namespace std;
SDL_Window *window1;
int background, windowWidth, windowHeight,windowXcoord,
windowYcoord;
SDL_Rect rectangle1;
SDL_Rect rectangle2;
SDL_Renderer *renderer;
int sequence1;
int sequence2;
void moveRectangle1(), moveRectangle2();
int main()
{
window1=nullptr;
background = 0xffffff;
windowWidth=700; windowHeight=500;
windowXcoord = 650; windowYcoord = 0;
window1 = SDL_CreateWindow("Main
Window",windowXcoord,windowYcoord, windowWidth,windowHeight,
SDL_WINDOW_SHOWN);
renderer = SDL_CreateRenderer( window1, -1 ,
SDL_RENDERER_ACCELERATED);
SDL_SetRenderDrawColor( renderer, 255, 255, 255, 255 );
SDL_RenderClear( renderer );
SDL_RenderPresent(renderer);
rectangle1.x = 100; rectangle1.y = 100; rectangle1.h = 40;
rectangle1.w = 40;
rectangle2.x = 100; rectangle2.y = 100; rectangle2.h = 40;
rectangle2.w = 40;
for (int i = 1;i<500;i++){
SDL_SetRenderDrawColor( renderer, 255, 255, 255,0 );
SDL_RenderClear( renderer );
// chequear return (cerrar programa)
moveRectangle1();
moveRectangle2();
SDL_RenderPresent(renderer);
usleep (12000);
}
return 0;
}
void moveRectangle1(){
sequence1++;
if (sequence1 <= 50){ rectangle1.x++; }
else if (sequence1 <= 100){ rectangle1.x--; }
else { sequence1 = 0; }
SDL_SetRenderDrawColor(renderer,255,0,0,255);
SDL_RenderFillRect(renderer, &rectangle1 );
}
void moveRectangle2(){
sequence2++;
if (sequence2 <= 100){ rectangle2.y++; }
else if (sequence2 <= 200){ rectangle2.y--; }
else { sequence2 = 0; }
SDL_SetRenderDrawColor(renderer,0,200,0,255);
SDL_RenderFillRect( renderer, &rectangle2 );
}